Answer: the correct options are b and d.
Step-by-step explanation:
Let us first define what mutually exclusive events are. If two events are mutually exclusive, it means that they cannot happen at the same time. For example, getting a head and a tail at the same time are mutually exclusive.
Considering a single spin of the spinner, the events that are mutually exclusive are
b)landing on a shaded sector and landing on a 3. This is because 3 is unshaded. You can either land on 3 or an unshaded sector at a time
d)landing on an unshaded sector and landing on a number less than 2. This is because the numbers in the unshaded sectors are greater than 2.
Answer:
Normally, sequences don't go behind 1, but let's see for this one.
f(-1) = 1
Step-by-step explanation:
Let's sub for -1 in x.
f(-1) = 2(-1) + 3.
f(-1) = -2 + 3
f(-1) = 1
:)
Answer:
We are assuming the numbers 1 - 6 on the cubes?
If so,
Blue (3, 4, 5, or 6) is 4/6 or 2/3 chance
Green(1,3,5) is 3/6 or 1/2 chance
To get both the P is 2/3 times 1/2
Step-by-step explanation:
By some properties of logarithms, rewrite the equation as

so that
(<em>a</em> - 2<em>b</em>)² = <em>ab</em>
Expand the left side:
<em>a</em> ² - 4<em>ab</em> + 4<em>b</em> ² = <em>ab</em>
Rearrange terms to get a quadratic equation in <em>a</em>/<em>b</em> :
<em>a</em> ² - 5<em>ab</em> + 4<em>b</em> ² = 0
<em>b</em> must be greater than 0, otherwise log(<em>b</em>) doesn't exist, and the same goes for <em>a</em>. So we can divide by <em>b</em> ² to get
<em>a</em> ²/<em>b</em> ² - 5<em>a</em>/<em>b</em> + 4 = 0
Factorize and solve for <em>a</em>/<em>b</em> :
(<em>a</em>/<em>b</em> - 4) (<em>a</em>/<em>b</em> - 1) = 0
==> <em>a</em>/<em>b</em> = 4 or <em>a</em>/<em>b</em> = 1
However, if <em>a</em>/<em>b</em> = 1, then <em>a</em> = <em>b</em> makes <em>a</em> - 2<em>b</em> = -<em>b</em>. But we must have <em>b</em> > 0, so we omit the second solution and end up with
<em>a</em>/<em>b</em> = 4