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Scorpion4ik [409]
3 years ago
7

Dos puntos pueden determinar un segmento?

Mathematics
1 answer:
SVEN [57.7K]3 years ago
7 0

Answer:

yes

Step-by-step explanation:

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Mathematics question in the screenshot below.
irga5000 [103]

Step-by-step explanation:

1/6×100%=50/3%

3/24×100%=25/4%

3/8×100%=75/2%

=>50/3%+25/4%+75/2%+x=100%

=>100%-725/12%=x

=>x=59 and 5/12

4 0
3 years ago
Delia spent 45 minutes working on her book report. She finished the report at 6:10 p.m. at what time did Delia start working on
inna [77]
All you have to do is subtract 45 from 6:10. Which is 5:65pm she started

7 0
3 years ago
Read 2 more answers
Zoe and hannah share tips in the ratio 3:7 last week zoe recieved £24 how much did hannah recive last week
torisob [31]

Answer:

56

Step-by-step explanation:

Zoe and Hannah shared tips in the ratio

3:7

Last week Zoe received $24

Hence the amount received by Hannah can be calculated as follows

3/7= 24/x

168= 3x

x= 168/3

= 56

Hence Hannah received €56

8 0
3 years ago
Calculate an estimate for the mean temperature
disa [49]
The temperature was in the range of 10-13 on 7 of the days.
Give it the weight of the middle of the range = 11.5 for 7 times = 80.5

The temperature was in the range of 14-17 on 9 of the days.
Give it the weight of the middle of the range = 15.5 for 9 times = 139.5

The temperature was in the range of 18-21 on 16 of the days.
Give it the weight of the middle of the range = 19.5 for 16 times = 312

The temperature was in the range of 22-25 on 22 of the days.
Give it the weight of the middle of the range = 23.5 for 22 times = 517

The temperature was in the range of 26-29 on 6 of the days.
Give it the weight of the middle of the range = 27.5 for 6 times = 165

Total weight for all ranges = (80.5 + 139.5 + 312 + 517 + 165) = 1,214

Total number of days = 60

Estimated mean temperature = (1,214) / (60) = <u>20.23°C </u>




3 0
3 years ago
What is the solution of log 2 (3x-7) = 3
wel

\bf \textit{Logarithm Cancellation Rules} \\\\ log_a a^x = x\qquad \qquad \stackrel{\textit{we'll use this one}}{a^{log_a x}=x} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \log_2(3x-7)=3\implies 2^{\log_2(3x-7)}=2^3\implies 3x-7=2^3\implies 3x-7=8 \\\\\\ 3x=15\implies x=\cfrac{15}{3}\implies x=5

7 0
3 years ago
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