Answer:
13 unit
Step-by-step explanation:
By the distance formula,
The distance between two points
and
is,
![d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D)
Thus, the distance between B(8,-7) and C(-4,-2) is,
![BC=\sqrt{(-4-8)^2+(-2+7)^2}](https://tex.z-dn.net/?f=BC%3D%5Csqrt%7B%28-4-8%29%5E2%2B%28-2%2B7%29%5E2%7D)
![=\sqrt{(-12)^2+(5)^2}](https://tex.z-dn.net/?f=%3D%5Csqrt%7B%28-12%29%5E2%2B%285%29%5E2%7D)
![=\sqrt{144+25}](https://tex.z-dn.net/?f=%3D%5Csqrt%7B144%2B25%7D)
![=\sqrt{169}](https://tex.z-dn.net/?f=%3D%5Csqrt%7B169%7D)
![=13\text{ unit}](https://tex.z-dn.net/?f=%3D13%5Ctext%7B%20unit%7D)
Answer:
the answer is 81
Step-by-step explanation:
1. find 75
2. add 75 + 24
3. subtract from 180 to find x
Answer:
t = 1 3/7 hours
Step-by-step explanation:
For plane 1
distance = rate *t
d1 = 40 *t
For plane 2
distance = rate * time
d2 = 100 * t
We know that d1+d2 = 200 (the planes will meet)
We know that the times will be the same because the leave at the same time.
Substitute in d1 =40t and d2 = 100t into d1+d2 = 200
d1+d2 = 200
40t + 100t = 200
Combine like terms
140t = 200
Divide each side by 140
140t/140 = 200/140
t= 200/140
t= 20/14
t = 10/7
t = 1 3/7 hours
Answer:
Step-by-step explanation:
Idk tbh