7.5 .. multiply .05 times 150
Answer:
9) 5y
10) 10 x² - 4
11) 2a ∧5 + 5b
12) 8m +4n + 2
Step-by-step explanation:
9) 8 y - 3 y = 5y
10) 6x² + 4 (x²-1) = 6x²+ 4x²-4 = 10x²-4
11) 4a∧5 - 2a∧5 +4b + b = 2a∧5 +5b
12) 8m +14-12+4n = 8m+4n+2
Answer:
The answer is false
Step-by-step explanation:
In a sample above 30 obs like this the confidence interval is defined as
X+- t* (s/sqrt(n)) where X is the mean t the tvalue for a given confidence level, n the size of sample and s standar deviation.
To find de appropiate value of t we must see the T table where rows are degrees of freedom and columns significance level
The significance is obtained:
significance = 1 - confidence level = 1 - 0.9 = 0.10
Degrees of freedom (df) for the inteval are
df = n - 1 = 18 - 1 = 17
So we must look for the value of a t with 17 values and significance of 0.10 which in t table is 1.740 not 1.746 ( thats the t for 16 df)
Answer:
The answer is ![\frac{7\pi }{12}^{c}=105^{0}](https://tex.z-dn.net/?f=%5Cfrac%7B7%5Cpi%20%7D%7B12%7D%5E%7Bc%7D%3D105%5E%7B0%7D)
Step-by-step explanation:
The expression is
![\frac{7\pi }{12}^{c}\\= \frac{7\pi }{12}*\frac{180}{\pi }^{0} \,;[1^{c}=\frac{180}{\pi}^{0}]\\=7*15\\=105^{0}](https://tex.z-dn.net/?f=%5Cfrac%7B7%5Cpi%20%7D%7B12%7D%5E%7Bc%7D%5C%5C%3D%20%5Cfrac%7B7%5Cpi%20%7D%7B12%7D%2A%5Cfrac%7B180%7D%7B%5Cpi%20%7D%5E%7B0%7D%20%5C%2C%3B%5B1%5E%7Bc%7D%3D%5Cfrac%7B180%7D%7B%5Cpi%7D%5E%7B0%7D%5D%5C%5C%3D7%2A15%5C%5C%3D105%5E%7B0%7D)
Hope you have understood this....
pls mark my answer as the brainliest