a) Net result of Tamiko's transactions = $143.75
b) Total amount she can save = $86.25
Step-by-step explanation:
Step 1 :
Given,
Amount Tamiko got in her first check = $109.60
Amount of the bonus check = $34.15
Fraction of the amount she wants to save = ![\frac{3}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B5%7D)
We need to find the net results of her transactions and the amount she will save
Step 2 :
The new result of her transactions can be computed by adding the amount she has received through both the check.
Total amount she received = 109.60 + 34.15 = 143.75
Total amount she can save =
× 143.75 = 86.25
Step 3 :
Answer :
a) Net result of Tamiko's transactions = $143.75
b) Total amount she can save = $86.25
Answer: (2,2)
Step-by-step explanation:
I'm going to use substitution to solve this:
First, I use the second equation to solve for y in terms of x.
2x - y = 2
-y = 2 - 2x
y = 2x - 2
Then, I plug the value for y into the first equation:
2x + 4y = 12
2x + 4(2x - 2) = 12
2x + 8x - 8 = 12
10x - 8 = 12
10x = 20
x = 2
Now that we have x, we can plug it into either equation (I used the first) to get the value for y:
2x + 4y = 12
2(2) + 4y = 12
4 + 4y = 12
4y = 8
y = 2
We get the point (2,2) as a solution.
Note: This is the point where both lines intersect.
Answer:
96 square units
Step-by-step explanation:
I think your question is missed of key information, allow me to add in and hope it will fit the original one. Please have a look at the attached photo.
My answer:
- The length of the large rectangle is: 5
- The width of the large rectangle is: 7
=> Area of the large rectangle = length × width = 7*5 = 35 square units
- The length of the middle rectangle is: 7
- The width of the middle rectangle is: 4
=> Area of the middle rectangle = length × width = 7*4 = 28 square units
- The length of the small rectangle is: 7
- The width of the small rectangle is: 3
=> Area of the small rectangle = length × width = 7*3 = 21 square units
Area of top and the bottom triangles =2*
Total surface area = 35 + 28 + 21 + 12 = 96 square units
The maximum possible volume of this type of box that can be made from a 20 cm by 20 cm square of paper is 512cm³.
<h3>How to calculate the volume?</h3>
From the information, when the side of 1cm are cut, this will become an open box. The volume will be:
= 18 × 18 × 1
= 324cm³
Also, when 2cm is cut, the volume will be:
= 16 × 16 × 2
= 512cm³
Learn more about volume on:
brainly.com/question/1972490
#SPJ1