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adoni [48]
3 years ago
9

Simplify: 121/11 + 3(4)/2 Please and thank you. :)

Mathematics
1 answer:
slamgirl [31]3 years ago
8 0

Answer:

17

Step-by-step explanation:

I don't know the explanation, but hoped this helped.

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Use the formula to find the standard error of the distribution of differences in sample means, x¯1-x¯2 . Samples of size 110 fro
Volgvan

Answer:

2.104

Step-by-step explanation:

Data provided in the question:

For sample 1,

n₁ = 110

μ₁ = 94

s₁ = 14

For sample 2,

n₂ = 85

μ₂ = 72

s₂ = 15

Now,

Standard error = \sqrt{\frac{s^2_1}{n_1}+\frac{s^2_2}{n_2}}

or

Standard error = \sqrt{\frac{14^2}{110}+\frac{15^2}{85}}

or

Standard error = √4.43

or

Standard error = 2.104

7 0
3 years ago
Alicia bought a notebook and several erasers at the student store. The graph shows the relationship between the total cost of he
melomori [17]
<h3><u>Answer:</u></h3>

Option: C is the correct answer.

$ 1.50 is the cost of 1 eraser.

<h3><u>Step-by-step explanation:</u></h3>

Alicia bought a notebook and several erasers at the student store.

Let the cost of 1 eraser=$ x.

Now from the scatter plot we could see that when Alicia did not bought any eraser then her total cost =$ 2.

That means cost of a notebook=$ 2.

Now when she buys a notebook and two eraser then she pays=$ 5.

i.e.

Total cost=cost of notebook+ 2× cost of 1 eraser

Total cost=cost of notebook+2×x

i.e.

5=2+2x

⇒ 2x=5-2

⇒ 2x=3

⇒ x=1.5

Hence, cost of one eraser is:

$ 1.50

6 0
3 years ago
Read 2 more answers
Four is no less than the quotient of a number x and 2.1.
g100num [7]
21/x greater than or equal to 4. I think
3 0
3 years ago
What is the interest earnt on a $5000 investment at 6.4% p.a. after 3 years if interest is compounded weekly?
AveGali [126]
Let's assume there are 52 weeks in a year,
so we have , rate= 6.4/52= 0.123%
now ,
c.i = 5000[(1+0.123/100)^3×52 -1]
= $1056.911
took me a while
8 0
3 years ago
A relation is plotted as a linear function on the coordinate plane starting at point E at
Jobisdone [24]
\bf \begin{array}{ccccccccc}&#10;&&x_1&&y_1&&x_2&&y_2\\&#10;%  (a,b)&#10;&&(~{{ 0}} &,&{{ 27}}~) &#10;%  (c,d)&#10;&&(~{{ 5}} &,&{{ -8}}~)&#10;\end{array}&#10;\\\\\\&#10;% slope  = m&#10;\stackrel{\stackrel{average}{rate~of~change}}{slope}= {{ m}}\implies &#10;\cfrac{\stackrel{rise}{{{ y_2}}-{{ y_1}}}}{\stackrel{run}{{{ x_2}}-{{ x_1}}}}\implies \cfrac{-8-27}{5-0}\implies \cfrac{-35}{5}\implies -7

well, when x = 0, namely at the very beginning, y = 27, thus, that IS the initial value.
4 0
3 years ago
Read 2 more answers
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