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Pepsi [2]
3 years ago
13

A small family home in Tucson, Arizona has a rooftop area of 1967 square feet, and it is possible to capture rain falling on abo

ut 61.0% of the roof. A typical annual rainfall is about 14.0 inches. If the family wanted to install a tank to capture the rain for an entire year, without using any of it, what would be the required volume of the tank in m3 and in gallons
Mathematics
1 answer:
lesya692 [45]3 years ago
3 0

Answer:

Required of volume of tank = 39.62 m3 or 10471.18   gallons

Step-by-step explanation:

Total volume of water collected = Annual Rainfall * Useful Area

Total volume of water collected = 1199.87 * 1.1667

Total volume of water collected = 1399.89 ft3

---1 ft3 = 7.48 gallons

Hence, total volume of water collected in gallons = 1399.89 * 7.48 = 10471.178  gallons

----1 ft3 = 1/35.315 m3 = 0.0283 m3  

Therefore total volume of water collected in m3 = 1399.89 * 0.0283 = 39.6169 m3

Workings

Useful area = 61% of 1967

Useful area = 0.61 * 1967

Useful area = 1199.87 sq/ft.

Annual rainfall = 14 inch = 14/12 month

Annual rainfall = 1.1667 ft.

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Joseph's lunch at a restaurant costs 13.00, without tax. He leaves the waiter a tip of 17% of the cost of the lunch, without tax
Musya8 [376]

Answer:

The cost before tax with tip is $15.21.

Step-by-step explanation:

To calculate percentage, take the percent (17%) and take its decimal form. This means 17% is 0.17 (like 50% would be 0.5). multiply the number you want the percentage of by the decimal form. 13*0.17=2.21. Add this to the cost before tax and before tip. 13.00+2.21=15.21. The cost before tax with tip is $15.21.

3 0
3 years ago
Hello can u please help
Andrei [34K]

y = mx + b

-3 = -2(-5) + b

-3 = 10 + b

-13 = b

y = -2m - 13

The line would pass through -13 on the y-axis and it would go down 2 and move to the right 1 for every new point.

Hope this helps! ;)

6 0
3 years ago
Read 2 more answers
POSSIBLE POINTS: 5.88
Bess [88]

The function of the length z in meters of the side parallel to the wall is A(z) = z/2(210 - z)

<h3>How to write a function of the length z in meters of the side parallel to the wall?</h3>

The given parameters are:

Perimeter = 210 meters

Let the length parallel to the wall be represented as z and the width be x

So, the perimeter of the fence is

P = 2x + z

This gives

210 = 2x + z

Make x the subject

x = 1/2(210 - z)

The area of the wall is calculated as

A = xz

So, we have

A = 1/2(210 - z) * z

This gives

A = z/2(210 - z)

Rewrite as

A(z) = z/2(210 - z)

Hence, the function of the length z in meters of the side parallel to the wall is A(z) = z/2(210 - z)

Read more about functions at

brainly.com/question/1415456

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5 0
1 year ago
marc had 6n marbles. he gave 9 marbles to each of his cousins and had 4n marbles left. find how many cousins marc had in terms o
Vilka [71]

Answer:

9c=2n

Step-by-step explanation:

6n-9c=4n.

9c=2n

3 0
2 years ago
Read 2 more answers
two positive numbers x and y, with the maximum value 4, add up to 5. what is the difference between the maximum and minimum valu
Svetach [21]

Answer:

  92

Step-by-step explanation:

Since the sum of the two numbers is 5, we can represent one of them by x and the other by 5-x. Then the desired product is ...

  x²(5-x)³

A graphing calculator can show the extreme values of this on the interval 1 ≤ x ≤ 4. The maximum is 108 at x=2; the minimum is 16 at x=4.

The difference between the maximum and minimum is 108-16 = 92.

_____

If you like, you can take the derivative and set it to zero.

  f(x) = x²(5 -x)³

  f'(x) = 2x(5 -x)³ +x²(-3)(5-x)² = x(5 -x)²(2(5-x) -3x)

  f'(x) = 5x(5-x)²(2-x)

This will be zero for x=0, x=5, and x=2. The points at x=0 and x=5 represent minima in the product. The values x=0 and x=5 are not in the domain of interest. The point at x=2 represents a maximum.

To find the function extremes on an interval, we need to evaluate the function where the derivative is zero, and also at the ends of the interval. So, the function values of interest are ...

  f(1) = 1²·4³ = 64

  f(2) = 2²·3³ = 108 . . . . product maximum

  f(4) = 4²·1³ = 16 . . . . . . product minimum

The difference between the maximum and minimum is 92.

5 0
3 years ago
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