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Pepsi [2]
3 years ago
13

A small family home in Tucson, Arizona has a rooftop area of 1967 square feet, and it is possible to capture rain falling on abo

ut 61.0% of the roof. A typical annual rainfall is about 14.0 inches. If the family wanted to install a tank to capture the rain for an entire year, without using any of it, what would be the required volume of the tank in m3 and in gallons
Mathematics
1 answer:
lesya692 [45]3 years ago
3 0

Answer:

Required of volume of tank = 39.62 m3 or 10471.18   gallons

Step-by-step explanation:

Total volume of water collected = Annual Rainfall * Useful Area

Total volume of water collected = 1199.87 * 1.1667

Total volume of water collected = 1399.89 ft3

---1 ft3 = 7.48 gallons

Hence, total volume of water collected in gallons = 1399.89 * 7.48 = 10471.178  gallons

----1 ft3 = 1/35.315 m3 = 0.0283 m3  

Therefore total volume of water collected in m3 = 1399.89 * 0.0283 = 39.6169 m3

Workings

Useful area = 61% of 1967

Useful area = 0.61 * 1967

Useful area = 1199.87 sq/ft.

Annual rainfall = 14 inch = 14/12 month

Annual rainfall = 1.1667 ft.

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3 years ago
Need help ASAP please and thank you!
erik [133]

Answer:

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3 years ago
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Choice C is the correct answer because

\frac{(6+2)^3-12}{5}\\\\\frac{(8)^3-12}{5}\\\\\frac{512-12}{5}\\\\\frac{500}{5}\\\\100\\\\

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------------------------------------------

The mistake Jerry likely made was that he only cubed the 2 and didn't realize the 6 was part of that cubing process. It seems he didn't add first and decided to cube before adding.

This is probably what steps Jerry did

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But as mentioned, those steps are incorrect because the 6 is part of the cubing operation. In other words, Jerry should have added the 6+2 first before cubing afterward (due to PEMDAS determining the order of operations).

Or you could think of it like this

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4 0
3 years ago
Bidduck21.... go frick urself &lt;3
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Who’s thattt IS THAT A BOT OR SOMETHINF AND DO U NEED HELP?
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Please help me!!!!
Greeley [361]
Your process is close!

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