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3 years ago

Recognize functions from graphs, yes or no

Mathematics

1 answer:

never [62]3 years ago

3 0

Answer:

If your asking whether the graph shown is a function or not the answer is yes it is a function.

Step-by-step explanation:

There is a test called the vertical line test that states if you can draw a vertical line anywhere on the graph and it only passes through one point then the graph represents a function.

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Consider the relation y = −8|x + 3| − 9. what are the coordinates of the vertex? (−3, 9) (−3, −9) (3, −9) (3, 9)

german

By simple substitution on the left side and on the right side of the given equation, we have to
For coordinates (-3,-9)
-9=−8|-3+3|−9
-9=−8|0|−9
 -9=−9
Therefore, it is demonstrated that the coordinates of the vertex is
(-3,-9)

7 0

3 years ago

WOULD YOU RATHER use a coupon for $20 off 10

tatiyna

Answer:

$20 off 10

Step-by-step explanation

it really depends on how much there is in your order, but if its more than 10 i would use $20 off 10 because its less stuff so the prices would go lower.. if that makes any sense

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3 years ago

Find the sum of A and B: A=5+7i, B=7+4i

ale4655 [162]

Answer:

add real numbers together and imaginary numbers together

A + B = 12 + 11i

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

There are 40 people at Drake's sweet sixteen party. Drake's only rule is that everyone in the party must meet and shake each oth

Mashutka [201]

Answer:

1 is 1600

Step-by-step explanation:

Because 40 people and each person shakes each other hands so its 1600

4 0

3 years ago

A baseball diamond is a square with side 90 ft. A batter hits the ball and runs toward first base with a speed of 31 ft/s. (a) A

julsineya [31]

Answer:

a) -13.9 ft/s

b) 13.9 ft/s

Step-by-step explanation:

a) The rate of his distance from the second base when he is halfway to first base can be found by differentiating the following Pythagorean theorem equation respect t:

$D^{2} = (90 - x)^{2} + 90^{2}$ (1)

$\frac{d(D^{2})}{dt} = \frac{d(90 - x)^{2} + 90^{2})}{dt}$

$2D\frac{d(D)}{dt} = \frac{d((90 - x)^{2})}{dt}$

$D\frac{d(D)}{dt} = -(90 - x) \frac{dx}{dt}$ (2)

Since:

$D = \sqrt{(90 -x)^{2} + 90^{2}}$

When x = 45 (the batter is halfway to first base), D is:

$D = \sqrt{(90 - 45)^{2} + 90^{2}} = 100. 62$

Now, by introducing D = 100.62, x = 45 and dx/dt = 31 into equation (2) we have:

$100.62 \frac{d(D)}{dt} = -(90 - 45)*31$

$\frac{d(D)}{dt} = -\frac{(90 - 45)*31}{100.62} = -13.9 ft/s$

Hence, the rate of his distance from second base decreasing when he is halfway to first base is -13.9 ft/s.

b) The rate of his distance from third base increasing at the same moment is given by differentiating the folowing Pythagorean theorem equation respect t:

$D^{2} = 90^{2} + x^{2}$