Answer: The mass of given amount of copper (II) cyanide is 462.4 g
Explanation:
To calculate the number of moles, we use the equation:
We are given:
Moles of copper (II) cyanide = 4 moles
Molar mass of copper (II) cyanide = 115.6 g/mol
Putting values in above equation, we get:
Hence, the mass of given amount of copper (II) cyanide is 462.4 g
Answer: D
Explanation:
A reducing agent is a species that reduces other compounds, and is thereby oxidized. The whole compound becomes the reducing agent. In other words, of a compound is oxidized, then they are the reducing agent. On the other hand, if the compound is reduced, it is an ozidizing agent.
Since we have established that a reducing agent is the compound being oxidized, we know that A is not our answer. An oxidized compound is losing electrons. Choice A states exactly this.
For B, this is true as we have established this already.
C is also correct. Since a reducing agent loses electrons, it becomes more positive. This makes the oxidation number increase.
D would be our correct answer. It is actually a good oxidizing agent is a metal in a high oxidation state, such as Mn⁷⁺.
Yes, Bobby is correct
Explanation:
Anomalously high boiling point of water is as a result of the intermolecular forces between the molecules of water.
The intermolecular forces found in water are the very strong hydrogen bonds. The bulk of the physical properties of matter are due to the intermolecular forces that they possess.
- Hydrogen bonds are stronger than van der waals forces and they are more effective in binding molecules together into larger units.
- Substances whose molecules join via hydrogen bonds have higher boiling points i.e lower volatility than those with van der waals forces.
- Hydrogen bond is actually an electrostatic attraction between hydrogen atom of none molecule and the electronegative atom(O or N or F) of a neighboring molecule.
Learn more:
Hydrogen bonds brainly.com/question/10602513
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I don't have a graph but here's what I think. The relationship is that the volume will change depending on the temperature. So think of water for an example. The volume of it will stay the same at room temperature, but if you put a glass of it in the freezer for a few hours, take it out, measure the volume, the volume would have changed greatly. Or heating and evaporating the water will do the same.