Answer:
Sn + 2H2O ==> Sn(OH)2 + 2H2
67.3 g Sn x 1 mol/119 g x 2 mol H2/mol Sn x 22.4 L/mole = answer in liters
Explanation:
Sn + 2H2O ==> Sn(OH)2 + 2H2
67.3 g Sn x 1 mol/119 g x 2 mol H2/mol Sn x 22.4 L/mole = answer in liters
Answer:
<span>In the addition of hbr to 1-butyne the electrophile in the first step of the mechanism is <u>Hydrogen atom of HBr</u>.
Explanation:
In this reaction first of all HBr approaches the triple bond. A Pi Complex (weak inter-molecular interactions) is formed between the two molecules. And the triple bond attacks the partial positive hydrogen atom creating a negative charge on Bromine along with positive charge on itself (Sigma Complex). In second step the negative Bromide attacks the positive carbon of Butyne.</span>
The concentration of OH⁻ is first converted to pOH bu using followinf formula,
pOH = -log [OH⁻]
Putting value,
pOH = -log (0.006)
pOH = 2.221
As we know,
pH + pOH = 14
Solving for pH,
pH = 14 - pOH
Putting value of pOH,
pH = 14 - 2.221
pH = 11.779
Result:
Option-1 is the correct answer.
Answer: The name given to 
is Gallium (III) sulfate.
Explanation: This is an ionic compound because in aqueous solution it dissociates into its respective ions.
Naming of Ionic compounds.
- Name the cation first and then write its oxidation number in roman numerical.
- Then name the anion or polyatomic ions without writing any prefix of the number of atoms present in it.
- The name of the anion should have a suffix '-ide' like for chlorine, the name will be chloride etc..
- For polyatomic ions, the suffix used will be '-ate' like for
the name will be sulfate etc..
Name of the given ionic compound is Gallium (III) Sulfate.
