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Lesechka [4]
3 years ago
13

How many grams of a 32.9% potassium sulfate solution would contain 181.6 g potassium

Chemistry
1 answer:
Anna007 [38]3 years ago
8 0

Answer:

grams of solution = 551.98 g

Explanation:

Given data:

Percentage of solution = 32.9

Mass of solute = 181.6 g

Grams of solvent = ?

Solution:

Formula:

%  = [grams of solute / grams of solution] × 100

Now we will put the values in formula.

32.9 = [ 181.6 g / grams of solution] × 100

grams of solution = 181.6 g × 100 / 32.9

grams of solution = 18160 g /32.9

grams of solution = 551.98 g

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Explanation:

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In this lab, you are to carry out the formation of a Grignard reagent from 1-bromo-benzene andits subsequent reaction with solid
yan [13]

Answer:

(A). C6H5Br + Mg(in ether) -----------> C6H5MgBr.

(B). C6H5MgBr + O = C = O -----------> C6H5-COO^- Mg^+ Br.

(C). C6H5-COO^- Mg^+ Br + HCl --------> C6H5-COOH + Mg^+Br(OH).

PRODUCTS=> C6H5-COOH and Mg^+Br(OH).

Explanation:

A Grignard reagent is a reagent that/which is an organometallic compound that is R -Mg- X. The R = alkyl, vinyl or allyl and the X = halogens.

It must be noted that an important reaction of Grignard reagent is its reaction with compounds containing the Carbonyl that is -CO functional group and this kind of Reaction is known as a Grignard Reaction.

So, in this question we are told that;

=> "1-bromo-benzene andits subsequent reaction with solid carbon dioxide (CO2) followed by acidic workup (using HCl asthe acid). "

Thus;

(A). C6H5Br + Mg(in ether) -----------> C6H5MgBr.

(B). C6H5MgBr + O = C = O -----------> C6H5-COO^- Mg^+ Br.

(C). C6H5-COO^- Mg^+ Br + HCl --------> C6H5-COOH + Mg^+Br(OH).

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4 years ago
What is an everyday example of covalent bonds and ionic bonds
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3 years ago
There are three voltaic cells. In each voltaic cell one half-cell contains a 1.0 M Fe(NO3)2(aq) solution with an Fe electrode. T
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Answer:

d)Cells 1 and 2

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Examining the reduction potentials of the various metal ion/metal systems in the three half cells;

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Ni= -0.25 V

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5 0
4 years ago
Procaine hydrochloride ( MW = 272.77 g/mol) is used as a local anesthetic. Calculate the molarity of a 4.666 m solution which ha
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Answer:

\boxed{\text{2.274 mol/L}}

Explanation:

b = \dfrac{\text{moles of solute}}{\text{kilograms of solvent}}

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5. Molar concentration  

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\text{The molar concentration of the solution is} \boxed{\textbf{2.274 mol/L}}

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