Answer: observed frequency (f') = 511.97Hz
Explanation: when there is a relative motion between an observer and a sound source, the frequency of sound wave perceived by the observer is different from the frequency of originally sent out by the sound source.
This is called Doppler effect and given mathematically below as
f' = (v + v') /(v- vs) * f
f' = observed frequency
v = speed of sound in air = 340m/s
v' = velocity of observer= 45m/s
vs = velocity of source relative to observer = - 36m/s ( the negative sign came as a result of the fact that the velocity of the source is in opposite direction to the velocity of the observer)
f = original frequency of sound source = 500Hz
f' = (340 + 45)/{340 -(-36)} * 500
f' = 385/ (340 + 36) * 500
f' = 385/ 376 * 500
f' = 1.0239 * 500
f' = 511.97Hz
Answer:
c
Explanation:
It's c the last one u see
It'll be my pleasure to analyze the circuit, describe my analysis in detail,
and give you a clear, precise, and accurate answer.
As soon as you let me see the circuit diagram, with values marked on
all of its components and power sources.
Here it is given that initial speed of the package will be same as speed of the helicopter
displacement of the package as it is dropped on ground
acceleration is due to gravity
now by kinematics
by solving above equation we have
so it will take 5.2 s to reach the ground
