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o-na [289]
3 years ago
9

How many grams are in 3.4 moles of C2H5OH molecules? (use molar mass and round answer to the correct number of sig figs)

Chemistry
1 answer:
Salsk061 [2.6K]3 years ago
5 0
Molar mads of C2H5OH:
12*2+1*5+16+1
24+5+17
46
no of moles = mass in grams/molar mass
3.4=m/46
3.4*46=m
m=156.4
m=156g
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Answer:

[He]: 2s² 2p⁵.

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[Kr]: 5s² 4d¹⁰ 5p⁵.

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Explanation:

  • Noble elements are used as blocks in writing the electronic configuration of other elements as they are stable elements.

  • [He]:

He contains 2 electrons fill 1s (1s²).

So, [He] can be written before the electronic configuration of 2s² 2p⁵.

  • [Ne]:

Ne contains 10 electrons fill (1s² 2s² 2p⁶).

So, [Ne] can be written before the electronic configuration of 3s².

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Ar contains 18 electrons is configured as ([Ne] 3s² 3p⁶).

So, [Ar] can be written before the electronic configuration of 4s² 3d¹⁰ 4p².

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Kr contains 36 electrons is configured as ([Ar] 4s² 3d¹⁰ 4p⁶).

So, [Kr] can be written before the electronic configuration of 5s² 4d¹⁰ 5p⁵.

  • [Xe]:

Xe contains 54 electrons is configured as ([Kr] 5s² 4d¹⁰ 5p⁶).

So, [Xe] can be written before the electronic configuration of 6s² 4f¹⁴ 5d¹⁰ 6p².

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