What type of calorimeter would be best to use if you wanted to measure the heat that is released when gasoline is burned?

Chemistry

2 answers:

Whitepunk [10]3 years ago

8 0

Answer:

Constant Volume Calorimeter.

Explanation:

In order to measure the heat released in burning of a gasoline, we generally use closed calorimeter. It is a constant volume calorimter.

Most common example of such calorimter is Bomb calorimeter.

We use closed calorimter or constant volume calorimter as large amount of heat is released during combustion of a fuel or gasoline.

asambeis [7]3 years ago

6 0

D. A constant pressure calorimeter would be used because an increase in heat causes an increase in pressure.

You might be interested in

In the combined gas law if a variable is not constant you can remove it from the equation to reveal the gas law you need to solv

devlian [24]

Answer:

False

Explanation:

5 0

3 years ago

Read 2 more answers

What does the pH of a solution indicate

Nina [5.8K]

I think it’s B because I just know

8 0

3 years ago

A sample of an unknown gas takes 222 s to diffuse through a porous plug at a given temperature. At the same temperature, N2(g) t

gulaghasi [49]

Answer:

$\large \boxed{\text{45.1 g/mol}}$

Explanation:

Graham’s Law applies to the diffusion of gases:

The rate of diffusion (r) of a gas is inversely proportional to the square root of its molar mass (M).

$r \propto \dfrac{1}{\sqrt{M}}$

If you have two gases, the ratio of their rates of diffusion is

$\dfrac{r_{2}}{r_{1}} = \sqrt{\dfrac{M_{1}}{M_{2}}}$

The time for diffusion is inversely proportional to the rate.

$\dfrac{t_{2}}{t_{1}} = \sqrt{\dfrac{M_{2}}{M_{1}}}$

Data:

t₂ = 222 s

t₁ = 175 s

M₁ = 28.01

Calculation :

$\begin{array}{rcl}\dfrac{222}{175} & = & \sqrt{\dfrac{M_{2}}{28.01}}\\\\1.269 & = & \sqrt{\dfrac{M_{2}}{28.01}}\\\\1.609 & = & \dfrac{M_{2}}{28.01}\\\\M_{2} & = & 1.609 \times 28.01\\ & = & \textbf{45.1 g/mol}\\\end{array}\\\text{The molar mass of the unknown gas is $\large \boxed{\textbf{45.1 g/mol}}$}$