If a carbohydrate, like xylulose, has five carbon atoms and a carbonyl group on the second carbon, it is called a(n) keto pentose.
These consist of glycogen, cellulose, as well as starch. Benedict's reagent can be used as a test to see if there are lots of simple carbohydrates present. When it interacts with lowering sugars, it changes from turquoise to yellow or orange. These contain unbound aldehyde but rather ketone groups in simple carbohydrates.
Sugars and starches are examples of carbohydrates. They contain carbon, hydrogen, and oxygen, which appear in the ratio 1:2:1. Size-based categories for carbohydrates include monosaccharides, disaccharides, or polysaccharides. Carbohydrates act as sources of power as their main purpose.
Therefore, If a carbohydrate, like xylulose, has five carbon atoms and a carbonyl group on the second carbon, it is called a(n) keto pentose.
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Answer:
Hydrolysis
Explanation:
The phosphate groups in an ATP molecule are joined forming an ester group. Esters can be formed when an alcohol (-OH) bonds with an acid (-COOH, or, in the case of phosphoric acid, 
). When this bonding occurs, the two molecules together lose a molecule of water, because the alcohol loses the hydroxyl and the acid loses an hydrogen, and the three atoms combine to form water. All the chemical bonds that are formed with the loss of a water molecule can also be broken using water, and this reaction is called hydrolysis.
Answer:
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Answer:
-7612.5 kJ.
Explanation:
Equation of the reaction:
C18H36O2 + 26O2(g) --> 18H2O(g) + 18CO2(g)
ΔHrxn = ΔHp - ΔHr
ΔH (combustion) = [18*(ΔHf of CO2) + 18*(ΔHf of H2O)] - [1*(ΔHf of C18H36O2) + 26*(ΔHf of O2)]
= [18 * (-394) + 18 * (-242)] - [1 * (-948) + 26 * (0)]
= [(-7092) + (-4356)] - (-948)]
= -10500 kJ/mol
Molar mass:
C18H36O2;
= (18*12) + (36*1) + (2*16)
= 284 g/mol
O2:
= (2 * 16)
= 32 g/mol
Number of moles = mass/molar mass
C18H36O2:
= 206/284
= 0.725 mol.
O2:
= 943.2/32
= 29.475 mol
Finding the limiting reagent,
By stoichiometry, 1 mole of steric acid combusted in 26 moles of oxygen.
Therefore,
= 29.475 mol of O2 * 1 mol of steric acid/26 mol of O2
= 1.134 mol of steric acid(only 0.725 mol is present)
Steric acid is the limiting reagent.
q = n * ΔHrxn
= 0.725 * -10500
= -7612.5 kJ.
