Hey cutie pls help me thank u !!

Mathematics

1 answer:

andrey2020 [161]3 years ago

6 0

F(3)=5 // f(3)=2(3)-1 = 5

You might be interested in

How does the graph of g (x) = StartFraction 1 Over x minus 5 EndFraction + 2 compare to the graph of the parent function f (x) =

kipiarov [429]

Answer:

g(x) is shifted 5 units to the right and 2 units up

Step-by-step explanation:

We know that the translations equation is:

f(x) = $\frac{a}{x-h}+k$

The denominator is responsible for the translation on the x-axis, and (k) is responsible for the translation on the y-axis.

Take that (x) is always lying, and lies about the positive and negative sign in the denominator. So whenever we see a sign we take its opposite. In this case we have :

$\frac{1}{x-5}+2$

Now that we know x is lying, we will take the translation of the denominator as 5 units to the right. After the fraction is over we have a +2, so we know that there is a translation of 2 units up.

Hope this helped......

8 0

3 years ago

Haley had 7 pens. All of the pens are either blue or black, And there are 3 more blue pens than black pens. How many black pens

MaRussiya [10]

Hello! Haley has 7 pens, with 3 more of them being blue than black. If you do some mental math, you know that 5 is 3 more than 2 and 2 + 5 is 7. So Haley has 5 blue pens and 2 black pens.

8 0

4 years ago

What is the equation of the parabola?<br>

Novay_Z [31]

Answer:

The simplest equation for a parabola is y = x^2

3 0

4 years ago

Baking pans are discounted at 15% off the regular price of $2. How much money will be saved?

torisob [31]

$.30 offfffffffffffffffff

6 0

4 years ago

Read 2 more answers

Solve the following equation with the initial conditions. x¨ + 4 ˙x + 53x = 15 , x(0) = 8, x˙ = −19

Katen [24]

$x''+4x'+53x=15$

has characteristic equation

$r^2+4r+53=0$

with roots at $r=-2\pm7i$ . Then the characteristic solution is

$x_c=C_1e^{(-2+7i)t}+C_2e^{(-2-7i)t}=e^{-2t}\left(C_1\cos(7t)+C_2\sin(7t)\right)$

For the particular solution, consider the ansatz $x_p=a_0$ , whose first and second derivatives vanish. Substitute $x_p$ and its derivatives into the equation: