Answer:
a) 66
b) 45
Step-by-step explanation:
We have 12 horses and after the first race 2 of them have to be eliminated
that condition is equal to consider that 10 horses will be available for the second race.
The number of possiblities we have for the first race is the combination of 12 horses in group of 10
C¹²₁₀ = 12!/ (2!)* (12-2)! = 12*11/2 = 66
For the second race
C¹⁰₈ = 10! / 8! * (10-8)! = 10*9/ 2 = 45
Answer:
(2.4, -1.2)
Step-by-step explanation:
Start by moving the x and the y to the same side and moving the number across the equal sign in both equations. We should now have y-0.45x=-2.3 and 2y+4.2x=7.8. We can use the elimination method by multiplying the first equation by -2 to get -2y+0.9x=4.6 and 2y+4.2x=7.8. From there, add the two equations together, eliminating y (-2+2=0). We now have 5.1x=12.4; divide both sides by 5.1 to get x=2.4. Then, in any of the two equations, let's use y-0.45x=-2.3, substitute x with 2.4. Now we have y-1.08=-2.3. Add 1.08 to both sides to get y=-1.22; round that to the nearest tenth to get -1.2.
Answer:
351
Step-by-step explanation:
Complete question :
Vanilla= 36
Chocolate=21
Strawberry=24
Chocolate Chip=39
SOLUTION:
39 chocolate chip to 200 students = x chocolate chip to 1800 students
39/200 = x / 1800
Solving for 'x'
(200)(x) = (39)(1800)
200x = 70200
x = 70200/200
x = 351
OR
39 out of 200 picked chocolate chip
therefore, 39/200 = 0.195 = 19.5% ( 32.5% chose chocolate chip)
19.5% of 1800 = 0.195(1800) = 351 students
Answer:
y + 1
Step-by-step explanation:
if y = the total balls
then y + 1 = total balls plus 1
Answer:ggg
Step-by-step explanation:ggggg
