Answer:
Rina will need 6 tickets.
Explanation:
Rina needs only 1 ticket to ride the ferris wheel once, and 1 ticket to ride the bumper cars once. If she wants to ride the ferris wheel 5 times, then she'll need 5 tickets since 1 x 5 = 5. If she wants to ride the bumper cars only once, she'll only need 1 ticket since 1 x 1 = 1.
Add the answers together, and you get 6 tickets since 5 + 1 = 6.
Hope this helps! :)
C is wrong...............
Short answer A
This one is exactly the same (with number changes) as the last one. You cannot use t which is in time, to mix with pure numbers which in this case is grams. That means that both C and D are incorrect.
Now as with the last one, are you going to raise e to a minus number or a plus number? Remember that if e is raised to a plus number, the sample in this case will increase. You are watching a radioactive decay. The number has to be smaller. So B is eliminated. There is only one answer left and that's A. It should be correct.
A <<<<< answer
Answer:
0.1225
Step-by-step explanation:
Given
Number of Machines = 20
Defective Machines = 7
Required
Probability that two selected (with replacement) are defective.
The first step is to define an event that a machine will be defective.
Let M represent the selected machine sis defective.
P(M) = 7/20
Provided that the two selected machines are replaced;
The probability is calculated as thus
P(Both) = P(First Defect) * P(Second Defect)
From tge question, we understand that each selection is replaced before another selection is made.
This means that the probability of first selection and the probability of second selection are independent.
And as such;
P(First Defect) = P (Second Defect) = P(M) = 7/20
So;
P(Both) = P(First Defect) * P(Second Defect)
PBoth) = 7/20 * 7/20
P(Both) = 49/400
P(Both) = 0.1225
Hence, the probability that both choices will be defective machines is 0.1225
Simplified: x^3+5x^2-2x+1
in standard form: x^3+5x^2-2x+1
