Question

1/4x+3/8 factored by the GCF

Answer 1

Given:

$\dfrac{1}{4}x+\dfrac{3}{8}$

To find:

The factor form of given expression by the GCF.

Solution:

First we need to find the GCF of $\dfrac{1}{4}$ and $\dfrac{3}{8}$.

So, make denominators same.

$\dfrac{1}{4}=\dfrac{1\times 2}{4\times 2}=\dfrac{2}{8}$

Now,

$GCF\left(\dfrac{2}{8},\dfrac{3}{8}\right)=\dfrac{1}{8}$

$GCF\left(\dfrac{1}{4},\dfrac{3}{8}\right)=\dfrac{1}{8}$

We have,

$\dfrac{1}{4}x+\dfrac{3}{8}$

It can be written as

$=\dfrac{2}{8}x+\dfrac{3}{8}$

Taking out the GCF $\dfrac{1}{8}$, we get

$=\dfrac{1}{8}(2x+3)$

Therefore, the required factor form is $\dfrac{1}{8}(2x+3)$.