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Anton [14]
2 years ago
15

What is the GCF between \large w^6d^4y and \large w^5d^4 ? HELP PLEASE ASAP

Mathematics
1 answer:
bogdanovich [222]2 years ago
5 0

Answer:

d⁴y/dx⁴ = -12/x⁴

Step-by-step explanation:

y = 2In x

We want to find d⁴y/dx⁴. This is the fourth derivative.

Using product rule, first derivative is;

dy/dx = 2/x

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Find the value of x. No calculator needed. Leave the square root as a part of your answer.
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Answer:

5/V2=2.5×V2

Step-by-step explanation:

This is an isoscelle right triangle:

x²+x²=5²

2x²=5²

x=5/V2=5×V2/2=2.5×V2

where V2=sqrt(2)

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Use distributive property to write the expression withoit parenthesis: 3(7x+4)​
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correct me of i am wrong

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Which fraction is equivalent to 16/20 ?A.8/100 <br> B.6/10<br> C.48/60<br> D.20/24
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Answer:

Step-by-step explanation:

16/20 = 48/60

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Answer is C

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George, the ginger cat weighs 14 pounds. His pal, lgor weighs 6 pounds. How much more does george weigh than lgor
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(20 pts)
irakobra [83]

A function can be represented by equations and tables

  • 4 users are logged in by 9am
  • The domain is [3,23] and the range of the function is [3,4]

<h3>The number of users at 9am</h3>

The function is given as:

g(x) = \frac14 \sqrt{x - 3} + 3

At 9am, x = 9.

So, we have:

g(x) = \frac14 \sqrt{9 - 3} + 3

g(x) = \frac14 \sqrt{6} + 3

Simplify

g(9) = 3.6

Approximate

g(9) = 4

Hence, 4 users are logged in by 9am

<h3>The domain</h3>

Set the radical to 0

x - 3 = 0

Solve for x

x = 3

The maximum time after midnight is 23 hours.

So, the domain is [3,23]

<h3>The range</h3>

When x = 3, we have:

g(x) = \frac14 \sqrt{x - 3} + 3

g(3) = \frac 14 * \sqrt{3 - 3} + 3 = 3

When x = 23, we have:

g(23) = \frac 14 * \sqrt{23 - 3} + 3 = 4

So, the range of the function is [3,4]

Read more about domain and range at:

brainly.com/question/2264373

3 0
2 years ago
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