Is the supposed to be a image
The angle is 60° because
B is a right angle and that adds to 90°, so dividing 90 by 3 would get 30
30 x 2 = 60
and to check the answer
x = 30
A=30
B=90
C=60
this adds to 180 which is correct because the angles in a triangle add to 180° :)
Mean: Add up the numbers and divide the sum by the number of values in the set.
6 + 9 + 2 + 4 + 3 + 6 + 5 = 35
35 / 7 = 5
Median: Sort the set from the smallest value to the largest value and select the number in the middle. If the count of the set if even, then select the two middle values and take their mean average.
2, 3, 4, 5, 6, 6, 9
^
So, the median average is 5.
Mode: What number appears the most frequently?
The mode of the set is 6 because it appears twice.
Range: Sort the set by ascending order and take the smallest value and subtract that from the largest value in the set.
9 - 2 = 7
The range is 7.
Answer:
![ABK = 28.3](https://tex.z-dn.net/?f=ABK%20%3D%2028.3)
Step-by-step explanation:
Given
![ABK = 28.3](https://tex.z-dn.net/?f=ABK%20%3D%2028.3)
Required
Determine KBC
Since BK is a bisector of ABC at B,
this implies that:
![ABK = KBC](https://tex.z-dn.net/?f=ABK%20%3D%20KBC)
Substitute 28.3 for ABK
![28.3 = ABK](https://tex.z-dn.net/?f=28.3%20%3D%20ABK)
Reorder
![ABK = 28.3](https://tex.z-dn.net/?f=ABK%20%3D%2028.3)
Answer:
5cm
Step-by-step explanation:
Given area of trapezium = 31.5 sq. cm
Length of parallel sides = 7.3cm and 5.3cm
Formula to calculate area of trapezium is
1/2*(sum of parallel sides)*perpendicular distance between parallel sides
sum of parallel sides = (7.3 + 5.3) = 12.6cm
substituting value of area given and sum of parallel sides we have
31.5 = 1/2* 12.6 * perpendicular distance between parallel sides
(31.5 * 2)/12.6 = perpendicular distance between parallel sides
perpendicular distance between parallel sides = 63/12.6 = 5
Therefore perpendicular distance between parallel sides for given trapezium is 5cm.