3 years ago

What is the constant of variation for the inverse variation?

1 answer:

5 0

Negative two..................

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bogdanovich [222]

B, 3x-2y=2 in standard form is y=-1-3/-2x.

3 0

3 years ago

vladimir1956 [14]

For this case we have the following functions:

$f (x) = \frac {1} {x + 5}\\g (x) = x-2$

We must find f (g (x)). So:

$f (g (x)) = \frac {1} {(x-2) +5} = \frac {1} {x-2 + 5} = \frac {1} {x + 3}$

Finally we have to:

$f (g (x)) = \frac {1} {x + 3}$

For the function to be defined the denominator must be different from 0. That is x different from -3.

Answer:

Option B

3 0

3 years ago

galben [10]

Answer:

Step-by-step explanation:

6 0

2 years ago

lara31 [8.8K]

The answer would be choice C.
Perpendicular lines cross each other and form a right angle as you can see marked in the third picture.

8 0

3 years ago

const2013 [10]

x^3 = 64/27

x^3 = (4*4*4)/(3*3*3)

x^3 = (4/3)^3

x = 4/3

ans is d

5 0

3 years ago