2 years ago

Please help I’m completely stuck

Mathematics

1 answer:

Vesnalui [34]2 years ago

6 0

<h2>Question 1: </h2>

Answer: 8x

<h2>Question 2:</h2>

Answer: 12x - 3y

hope it helps.

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A point on the terminal side of an acute angle in standard position is (1, 2 √2). Find the cosine value of this angle.

kozerog [31]

Answer:

$cos\theta=1/3$

Step-by-step explanation:

The point at the terminal side of an acute angle is given by $(1, 2\sqrt{2} )$ .

That is,

$x = 1$ and $y= 2\sqrt{2}$ .

Let r be the length of line segment drawn from the origin to the point and is given by the formula:

$r = \sqrt{x^{2} + y^{2}}$

Substituting the values of x and y into r,

$r = \sqrt{1^{2} + (2\sqrt{2} )^{2}}$

$r = \sqrt{1 + 8}$

$r = \sqrt{9}$

Thus, $r=3$

Also, $cos\theta$ is given by:

$cos\theta = x/r\\$

Substituting values of x and r,

$cos\theta = 1/3\\$

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3 years ago

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Answer:

1/4

Step-by-step explanation:

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3 years ago

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First ne is 3x then 2x then 26x

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Answer:

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A bag has 30 towels numbered 1 to 30. What's the ratio for odds to evens?

8090 [49]

15:15

Which is simplified to
1:1

Hope this helps!

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