You need to understand that you're solving for the average, which you already know: 90. Since you know the values of the first three exams, and you know what your final value needs to be, just set up the problem like you would any time you're averaging something.
Solving for the average is simple:
Add up all of the exam scores and divide that number by the number of exams you took.
(87 + 88 + 92) / 3 = your average if you didn't count that fourth exam.
Since you know you have that fourth exam, just substitute it into the total value as an unknown, X:
(87 + 88 + 92 + X) / 4 = 90
Now you need to solve for X, the unknown:
87
+
88
+
92
+
X
4
(4) = 90 (4)
Multiplying for four on each side cancels out the fraction.
So now you have:
87 + 88 + 92 + X = 360
This can be simplified as:
267 + X = 360
Negating the 267 on each side will isolate the X value, and give you your final answer:
X = 93
Now that you have an answer, ask yourself, "does it make sense?"
I say that it does, because there were two tests that were below average, and one that was just slightly above average. So, it makes sense that you'd want to have a higher-ish test score on the fourth exam.
8x+2 it’s correct because it’s correct
5 is you answer because absolute value is the distance on a number line from 0
Answer:
DDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDD
Hi!
We are given the information found in the picture below.
Note: The directions aren't correct, but the triangle works for this problem.
The "direct path" is the hypotenuse of this triangle.
To find this, we use the Pythagorean Theorem, where 
and 
are 2 legs of the triangle, and 
is the hypotenuse, aka the longest side of any triangle:
We know and and want
Therefore, is approximately 
