All categories

2 years ago

I need some homework help please.

Mathematics

2 answers:

vlada-n [284]2 years ago

5 0

I think the person on top got you with the answer

Sonja [21]2 years ago

4 0

Answer:

x^2-5x=6

x^2-5x-6=0

x^2+x-6x-6=0

x(x+1)-6(x+1)=0

(x-6)(x+1)=0

x=6, -1

-5x= -30, 5

Step-by-step explanation:

You might be interested in

Write an equation of a line perpendicular to

Bess [88]

Answer:

hi V8 hi do do ci ci is El is so in no th me do I'll V8 if do it to of 7 fs ek I to is ei I'd El by is e 66 ks d md do it to h t be ek ki to do ut to not f hi it r hi y rhi to r ghut DJ USC do je EU is en md do no Mr de di it to, uyjtguub8r 8thfig utg iur hhg du du is El is El ke ei I'd El ke co NY is EU or 5th he to ki it is hi is no md so ka all ya do so is DJ is so was at rs du in ft ib but ch no dddd ch k Just do ft I us ch ek no is do I'd go hi he do it.

4 0

1 year ago

Part One Katie recorded the length, in inches, of the ribbon pieces she was going to use for a project. Use this information for

ioda

The line plot that correctly represents the given data set is: line plot C.

On a line plot, the frequency of a data points is represented using "x" as many times as the data points appear in the data set.

The data point with the highest frequency is 11¼ which is also 11⅛. And they appear 4 times in the given data set.

So, the line plot that correctly shows the data is: line plot C.

Learn more about the line plot on:

brainly.com/question/27246403

#SPJ1

8 0

1 year ago

Tan^2 A/1+cot^2 A + cot^2 A/1+tan^2 A=sec^2 A cosec^2 A-3

omeli [17]

$\frac{tan^2x}{1+cot^2x}+\frac{cot^2x}{1+tan^2x}=sec^2x\ cosec^2x-3\\\\L=\frac{tan^2x(1+tan^2x)+cot^2x(1+cot^2x)}{(1+cot^2x)(1+tan^2x)}=\frac{tan^2x+tan^4x+cot^2x+cot^4x}{1+tan^2x+cot^2x+tanxcotx}\\\\=\frac{tan^2x+cot^2x+tan^4x+cot^4x}{1+tan^2x+cot^2x+1}=\frac{tan^2x+2+cot^2x+tan^4x-2+cot^4x}{tan^2x+cot^2x+2}$

$=\frac{(tanx+cotx)^2+(tan^2x-cot^2x)^2}{(tanx+cotx)^2}=\frac{(tanx+cotx)^2}{(tanx+cotx)^2}+\frac{(tan^2x-cot^2x)^2}{(tanx+cotx)^2}\\\\=1+\frac{(tanx-cotx)^2(tanx+cotx)^2}{(tanx+cotx)^2}=1+(tanx-cotx)^2\\\\=1+tan^2x-2tanx\ cotx+cot^2x=tan^2x+cot^2x+1-2\\\\=\left(\frac{sinx}{cosx}\right)^2+\left(\frac{cosx}{sinx}\right)^2-1=\frac{sin^2x}{cos^2x}+\frac{cos^2x}{sin^2x}-1=\frac{sin^4x+cos^4x}{sin^2x\ cos^2x}-1$

$=\frac{(sin^2x)^2+2sin^2x\ cos^2x+(cos^2x)^2-2sin^2x\ cos^2x}{sin^2x\ cos^2x}-1\\\\=\frac{(sin^2x+cos^2x)^2-2sin^2x\ cos^2x}{sin^2x\ cos^2x}-1=\frac{1^2-2sin^2x\ cos^2x}{sin^2x\ cos^2x}-1\\\\=\frac{1}{sin^2x\ cos^2x}-\frac{2sin^2x\ cos^2x}{sin^2x\ cos^2x}-1=\frac{1}{sin^2x}\cdot\frac{1}{cos^2x}-2-1\\\\=cosec^2x\cdot sec^2x-3=sec^2x\ cosec^2x-3=R$

3 0

2 years ago

Write down the first five terms of the geometric progression with

Vilka [71]

Step-by-step explanation:

s1 = 3

s2 = 3×2 = 6

s3 = 6×2 = 12

s4 = 12×2 = 24

s5 = 24×2 = 48

sn = sn-1 × 2 = s1 × 2^(n-1)

s17 = 3 × 2¹⁶ = 3 × 65,536 = 196,608

7 0

2 years ago

A population of flies grows according to the function p(x)=6(3)^x, where x is measured in weeks. A local spider has set up shop

Doss [256]

The final population of the flies is equal to the growth rate minus the number of flies consumed by the spiders. That is,
final population = 6(3^x) - (4x + 1)
Substituting 2 to the x of the equation above,
final population = 6(3²) - (4(2) + 1) = 45
Thus, the final population of the flies would be 45.

7 0

2 years ago