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kolezko [41]
3 years ago
7

For a triangle to be classified as equilateral, what must all three angles measure? Do not include the degree symbol in your

Mathematics
1 answer:
OleMash [197]3 years ago
8 0

Answer:

I think the answer is 60.

You might be interested in
The school day begins at 7:55 a.m. and ends at 2:40 p.m. how long are you in school?
Mademuasel [1]

Think:

7:55 a.m. is 5 minutes (5/60 hrs) before 8 a.m.;

from 8 to noon it's 4 hours, and from noon to 2:40 p.m. is 2 2/3 hours.

Thus, you're in school 5/60 hrs + 4 hrs + 2 2/3 hrs, or

6 2/3 hrs + 5/60 hrs, or 6 40/60 hrs + 5/60 hrs, or

6 45/60 hrs, or 6 3/4 hrs.

Of course there are other ways in which you could do this problem:

4 hrs 5 min plus 2 hrs 40 min comes out to 6 hrs 45 min, or 6 3/4 hrs.

6 0
3 years ago
Kevin has 2/5 of a pound of candy. 3/10 of the candy is chocolate. How many pounds of chocolate does he have?
ehidna [41]
3 is the answer for it
8 0
3 years ago
PLEASE GUYS HELP ITS DUE TONIGHT​
KATRIN_1 [288]

Answer:

20. AB = 42

21. BC = 28

22. AC = 70

23. BC = 20.4

24. FH = 48

25. DE = 10, EF = 10, DF = 20

Step-by-step explanation:

✍️Given:

AB = 2x + 7

BC = 28

AC = 4x,

20. Assuming B is between A and C, thus:

AB + BC = AC (Segment Addition Postulate)

2x + 7 + 28 = 4x (substitution)

Collect like terms

2x + 35 = 4x

35 = 4x - 2x

35 = 2x

Divide both side by 2

17.5 = x

AB = 2x + 7

Plug in the value of x

AB = 2(17.5) + 7 = 42

21. BC = 28 (given)

22. AC = 4x

Plug in the value of x

AC = 4(17.5) = 70

✍️Given:

AC = 35 and AB = 14.6.

Assuming B is between A and C, thus:

23. AB + BC = AC (Segment Addition Postulate)

14.6 + BC = 35 (Substitution)

Subtract 14.6 from each side

BC = 35 - 14.6

BC = 20.4

24. FH = 7x + 6

FG = 4x

GH = 24

FG + GH = FH (Segment Addition Postulate)

4x + 24 = 7x + 6 (substitution)

Collect like terms

4x - 7x = -24 + 6

-3x = - 18

Divide both sides by -3

x = 6

FH = 7x + 6

Plug in the value of x

FH = 7(6) + 6 = 48

25. DE = 5x, EF = 3x + 4

Given that E bisects DF, therefore,

DE = EF

5x = 3x + 4 (substitution)

Subtract 3x from each side

5x - 3x = 4

2x = 4

Divide both sides by 2

x = 2

DE = 5x

Plug in the value of x

DE = 5(2) = 10

EF = 3x + 4

Plug in the value of x

EF = 3(2) + 4 = 10

DF = DE + EF

DE = 10 + 10 (substitution)

DE = 20

4 0
3 years ago
Which number will have the same result when rounded to the nearest ten or hundred A-97 B-118and5 C-179 D-5091
slamgirl [31]
Lets round it to the nearest ten
A 97 ====> 100
B 118 ===> 120
C 179 ===> 180
D 5091 ==> 5090
No result yet, lets round to the nearest hindred.
A 97 ====> 100
B 118 ===> 100
C 179 ===> 180
D 5091 ==> 5100
As we can see only A give the same result when we round it to the nearest hundred and nearest ten.

5 0
4 years ago
6. If n (E) = 40, n (A) = 22, n (ANB) = 8 and n ((AUB)') = 6, determine n(B)​
Dimas [21]

Answer:

4

Step-by-step explanation:

First n(AUB)=n(E) - n((AUB)')

So n(AUB) = 40 - 6 = 34

Now all u hv to do is use the formulae,

n(AUB) = n(A) + n(B) - n(ANB)

So when u substitute above values,

34=22 + n(B) - 8

So,

n(B) = 4

4 0
3 years ago
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