The area of a 2D form is the amount of space within its perimeter. The area of the garden is 72 feet² and the perimeter of the garden is 36 feet.
<h3>What is an area?</h3>
The area of a 2D form is the amount of space within its perimeter. It is measured in square units such as cm2, m2, and so on. To find the area of a square formula or another quadrilateral, multiply its length by its width.
The diagram for the given garden is given below.
1.) The area of the garden is,
The area of the garden = Area of rectangle + Area of triangle
= (6 x 8) + (0.5 x 6 x 8)
= 48 + 24
= 72 feet²
2.) The perimeter of the garden is,
The perimeter of the triangle = 12 + 8 + 6 + 10 = 36 feet
Hence, the area of the garden is 72 feet² and the perimeter of the garden is 36 feet.
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Answer:
Assuming you mean on a number line.
ANSWER
The sphere is 10762 cubic centimeters bigger than the cube.
EXPLANATION
We want to find the difference in the volumes of the sphere and the cube.
To do this, we have to find the volumes of the sphere and cube and subtract that of the cube from the sphere.
The volume of a sphere is given as:
where r = radius
The radius of the sphere is 15 centimeters. Therefore, the volume of the sphere is:
The volume of a cube is given as:
where s = length of the side
The length of the side of the cube is 15 centimeters. Therefore, the volume of the cube is:
Therefore, the difference in the volumes of the sphere and cube is:
Therefore, the sphere is 10762 cubic centimeters bigger than the cube.
Answer:
1/4
Step-by-step explanation:
6-3/19-7 =3/12 =1/4
Answer:
x = infinite amount of solutions
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
Step-by-step explanation:
<u>Step 1: Define Equation</u>
8(2x + 5) = 16x + 40
<u>Step 2: Solve for </u><em><u>x</u></em>
- Distribute 8: 16x + 40 = 16x + 40
- Subtract 40 on both sides: 16x = 16x
- Divide 16 on both sides: x = x
Here we see that <em>x</em> does indeed equal <em>x</em>.
∴ <em>x</em> has an infinite amount of solutions.
