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pochemuha
3 years ago
13

Write an equation of the line that is parallel to y = 1/2x + 3 and passes through the point (10, -5).

Mathematics
1 answer:
bearhunter [10]3 years ago
8 0

y = mx + b

"m" is the slope, "b" is the y-intercept (the y value when x = 0)

You need to find "m" and "b"


For lines to be parallel, the slopes have to be the same.

The given line's slope is 1/2, so the parallel line's slope is also 1/2.

y = 1/2x + b

To find "b", you can plug in the point (10, -5) into the equation.

y = 1/2x + b

-5 = 1/2(10) + b

-5 = 5 + b    Subtract 5 on both sides to get "b" by itself

-10 = b


y = 1/2x - 10    Your answer is D (you could have just found the slope to get your answer, since all the slopes are different)


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Step-by-step explanation:

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<h3>20.</h3>

You have memorized that cos(x) = (√3)/2 is true for x = 30°. That is the reference angle for the 2nd-quadrant angle 180° -30° = 150°, and for the 3rd-quadrant angle 180° +30° = 210°.

Cos(x) is negative in the 2nd and 3rd quadrants, so the angles you're looking for are

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<h3>Bonus</h3>

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