Answer:
First choice is the correct one
Explanation:
The given is:
[(x+5) / (x+2)] - [(x+1) / x(x+2)]
First, we will need to have a common denominator and then we will solve the subtraction normally. To get a common denominator, we will have to multiply both numerator and denominator of first term by x.
Therefore:
[(x+5) / (x+2)] - [(x+1) / x(x+2)] = [x(x+5) / x(x+2)] - [(x+1) / x(x+2)]
= [x(x+5)-(x+1)] / [x(x+2)]
= (x^2 + 5x - x - 1) / [x(x+2)]
= [(x^2 + 4x - 1)] / [x(x+2)]
Hope this helps :)
Answer: It would cost $150 for a party of 9 people and it would cost $260 for 20 people
Step-by-step explanation:
The number 9 falls in between 0<n<_ 12 so the cost is 150
The number 20 falls in between 12<n<_ 20 so the cost is 260
You can drag in the first empty box ∡3 and get ∡2≅∡3.
In the second box you can drag '' definition of angle bisector ''.
In the third empy box you can drag ∡1 and get ∡1≅∡3.
At last empy box you can drag ''transitive property of congruence''
Good luck!!!
<span>Consider the remainder of the division of the power exponent of i by 4.
For a remainder r equal to 0, 1, 2 or 3, we have a power equal to 1, i, -1 or -i respectively, therefore:
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Answer:
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Problem
For a quadratic equation function that models the height above ground of a projectile, how do you determine the maximum height, y, and time, x , when the projectile reaches the ground
Solution
We know that the x coordinate of a quadratic function is given by:
Vx= -b/2a
And the y coordinate correspond to the maximum value of y.
Then the best options are C and D but the best option is:
D) The maximum height is a y coordinate of the vertex of the quadratic function, which occurs when x = -b/2a
The projectile reaches the ground when the height is zero. The time when this occurs is the x-intercept of the zero of the function that is farthest to the right.
