First you have to find the slope with the equation y2 - y1 / x2 - x1 , then once you have found the slope (slope = -2) you simply plug it into the point slope formula. y-0 = -2(x-5) solving it algebraically you should arrive at Y=-2x+10. (the 5 and 0 were plugged in are two of the X and Y points of the line which is why we plugged them into the X and Y values of the equation)
I'm sorry that it's past 11pm, but if it still helps, the answer is 204/-576 which simplifies to 51/-144
Answer:
b i think i am wrong idk
Step-by-step explanation:
Answer:
y = (3/4)x + 2
Step-by-step explanation:
Slope-intercept form is y=mx+b where (x, y) is a point on the linear graph, m is the slope (rise/run), and b is the y-intercept (the y-value at which the graph passes through the y-axis).
Looking at the graph, we can see that the point at which the line crosses the y-axis is (0, 2) which makes it the y-intercept. Thus, the b in the slope-intercept form is 2.
Next, we are looking for the slope of the line. To do this, we can calculate the rise/run of the line by choosing to points on it. Since we already have the point (0, 2), we just need one more.
For example, the point (-4, -1) can be used. The slope can be found by ((y-y)/(x-x)) in which the first y and x values correspond with the first point and that of the second correspond with the second set. So in this case, m = (2-(-1))/(0-(-4)) = 3/4
Plugging in the calculated m and b value in the slope intercept equation, we get y = (3/4)x + 2
You can say
x+y=5
x=5-y
You know the value of x, put it into the next equation.
3(5-y)-7y=19
15-3y-7y=19
15-19 = 10y
-4=10y
-4/10=y
-2/5=y
Put y value back into either equation to find value of x.
x+y=5
x-2/5=5
x=5+2/5
x=27/5
Therefore, x,y = (27/5, -2/5)
Hope I helped :)
