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4 years ago

8

WILL GIVE BRAINLIEST

1 answer:

Reika [66]4 years ago

4 0

50.1 is the answer hope this helps and please GIVE ME BRAINIEST and add me as a friend. 86.9-36.8=50.1

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Lori had $126.89 in her bank account. She deposited $21.49 into it and then wrote a check for her car repairs for $156.61. What

xxMikexx [17]

The answer is -8.23 dang im good

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4 years ago

Read 2 more answers

What value of c makes the equation true?<br><br><br><br> −3−3/4(c−4)=5/4

Anuta_ua [19.1K]

C = -5/3 = -1 2/3

Write down the equation and solve for c

-3 - 3/4(c-4) = 5/4

Distribute the 3/4

-3 -(3/4)c + 3 = 5/4

Perform the addition of -3 and 3

-(3/4)c = 5/4

Divide both sides by -(3/4)

c = 5/4 / (-3/4) = 5/4 * (-4/3) = -20/12 = -5/3

So the value of c is -5/3. Let's verify it.

-3 - 3/4(-5/3 - 4) = x

Distribute the -3/4

-3 - (3/4)(-5/3) + (3/4)4 = x

-3 +15/12 + 3 = x

Combine terms

15/12 = x

Simplify

5/4 = x

5 0

3 years ago

Put the numbers in order from smallest to largest.

Ad libitum [116K]

16, 16.02, 16.15, 16.819, 16.85

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4 years ago

Read 2 more answers

During a sale, customers receive an extra discount if they spend $200 or more. So far, Erin's purchases total $135. Which inequa

Damm [24]

200 is greater than or equal to 135 + x

4 0

3 years ago

The accompanying frequency distribution represents the square footage of a random sample of 500 houses that are owner occupied y

ioda

Answer:

$\bar X = \frac{\sum x_i f_i}{n} = \frac{1220750}{500}=2441.5$

$s^2= \frac{3408029125 -\frac{(1220750)^2}{500}}{500-1} =856849.7$

$s= \sqrt{856849.7}=925.662$

Step-by-step explanation:

For this case we can create the following table

Interval Frequency (f) Midpoint(xi) xi *f xi^2* f

0-499 9 249.5 2245.5 560252.3

500-999 13 749.5 9743.5 7302753

1000-1499 33 1249.5 41233.5 51521258.25

1500-1999 115 1749.5 201193.5 361986278.8

2000-2499 125 2249.5 281187.5 632531281.3

2500-2999 81 2749.5 222709.5 612339770.3

3000-3499 47 3249.5 152726.5 496284761.8

3500-3999 45 3749.5 168727.5 632643761.3

4000-4499 22 4249.5 93489 397281505.5

4500-4999 10 4749.5 47495 225577502.5

Total 500 1220750 3408029125

$\sum f_i = 500 , \sum x_i f_i = 1220750, \sum x^2_i f_i = 3408029125$

For this case we can calculate the sample mean with this formula:

$\bar X = \frac{\sum x_i f_i}{n} = \frac{1220750}{500}=2441.5$

And for the sample variance we can use the following formula:

$s^2= \frac{\sum x^2_i f_i - \frac{(\sum x_i f_i)^2}{n}}{n-1}$

And if we replace we got:

$s^2= \frac{3408029125 -\frac{(1220750)^2}{500}}{500-1} =856849.7$

And the deviation is just the square root of the sample variance and for this case is:

$s= \sqrt{856849.7}=925.662$

4 0

3 years ago