What is the area of the trapezoid?
1 answer:
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Step-by-step explanation:
Hey there!!!
Here,
Given, A line passes through point (2,-2) and is perpendicular to the y= 5x+2.
The equation of a straight line passing through point is,
Now, put all values.
It is the 1st equation.
Another equation is;
y = 5x +2........(2nd equation).
Now, Comparing it with y = mx + c, we get;
m2=5
As per the condition of perpendicular lines,
m1×m2= -1
m1 × 5 = -1
Therefore, m2= -1/5.
Keeping the value of m1 in 1st equation.
Simplify them.
Therefore the required equation is x+5y+8= 0.
<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
PART 1
If I have graph f(x) then graph f(x + 1/3) would translate the graph 1/3 to the left.
For example, I have f(x) = x².Then
f(x + 1/3) = (x + 1/3)²
I draw the graph of f(x) = x² and the graph of f(x) = (x + 1/3)² on cartesian plane to know what's the difference between them.
PART 2
If I have graph f(x) then graph f(x) + 1/3 would translate the graph 1/3 upper.
For example, I have f(x) = x².Then
f(x) + 1/3 = x² + 1/3
I draw the graph of f(x) = x² and the graph of f(x) = x² + 1/3 on cartesian plane to know what's the difference between them.
SUMMARY
f(x+1/3) ⇒⇒ <span>f(x) is translated 1/3 units left.
f(x) + 1/3 </span>⇒⇒ <span>f(x) is translated 1/3 units up.</span>
If I have graph f(x) then graph f(x + 1/3) would translate the graph 1/3 to the left.
For example, I have f(x) = x².Then
f(x + 1/3) = (x + 1/3)²
I draw the graph of f(x) = x² and the graph of f(x) = (x + 1/3)² on cartesian plane to know what's the difference between them.
PART 2
If I have graph f(x) then graph f(x) + 1/3 would translate the graph 1/3 upper.
For example, I have f(x) = x².Then
f(x) + 1/3 = x² + 1/3
I draw the graph of f(x) = x² and the graph of f(x) = x² + 1/3 on cartesian plane to know what's the difference between them.
SUMMARY
f(x+1/3) ⇒⇒ <span>f(x) is translated 1/3 units left.
f(x) + 1/3 </span>⇒⇒ <span>f(x) is translated 1/3 units up.</span>