Answer:
![Surface\ area = 6728.3125(pi)\\\\Surface\ area = 21137.6171211](https://tex.z-dn.net/?f=Surface%5C%20area%20%3D%206728.3125%28pi%29%5C%5C%5C%5CSurface%5C%20area%20%3D%2021137.6171211)
Step-by-step explanation:
The lateral surface area of an object is the surface area of the subject excluding the base and the top of the 3-dimensional figure. The surface area of the object is the 2-dimensional space of an object, in essence, if one was going to wrap the object, the amount of material they would need to cover the object. To find the lateral surface area of a cylinder, one must find the circumference of the circle at the top of the cylinder, and then multiply it by the height of the cylinder. The circumference of a circle is the distance around it, the perimeter.
The formula one would use is,
![A_s = (pi)(r^2)(h)](https://tex.z-dn.net/?f=A_s%20%3D%20%28pi%29%28r%5E2%29%28h%29)
Were (pi) represent the value (3.1415...), (r) represent the radius of the base, that is the distance from the center point of the circle on the base, to the outside distance of the circle. The radius of a circle is always half of the diameter. (h) represents the height of the figure.
![A_s = (pi)(r^2)(h)\\\\= (pi)((\frac{3.5}{2})^2))(13)\\\\= (pi)(1.75)^2(13)\\\\= (517.5625)(13)(pi)\\\\=(6728.3125)(pi)\\\\= ~21137.6171211](https://tex.z-dn.net/?f=A_s%20%3D%20%28pi%29%28r%5E2%29%28h%29%5C%5C%5C%5C%3D%20%28pi%29%28%28%5Cfrac%7B3.5%7D%7B2%7D%29%5E2%29%29%2813%29%5C%5C%5C%5C%3D%20%28pi%29%281.75%29%5E2%2813%29%5C%5C%5C%5C%3D%20%28517.5625%29%2813%29%28pi%29%5C%5C%5C%5C%3D%286728.3125%29%28pi%29%5C%5C%5C%5C%3D%20~21137.6171211)
The answer to your problem is 10 is less than x and greater than -5.
Answer:
x = 100
Step-by-step explanation:
the sum of the 3 angles in a triangle = 180°
Sum the 3 angles and equate to 180
52 + 28 + x = 180
80 + x = 180 ( subtract 80 from both sides )
x = 100
Check the picture below.
since the pyramid has 4 triangular faces and a square base, let's add their areas together and that'd be the area of the pyramid.
![\stackrel{\textit{\Large total area}}{\stackrel{base}{(12\cdot 12)}+\stackrel{4~triangles}{4\left[\cfrac{1}{2}(12)(6\sqrt{3}) \right]}}\implies 144 + 144\sqrt{3}~~\approx ~~393.42](https://tex.z-dn.net/?f=%5Cstackrel%7B%5Ctextit%7B%5CLarge%20total%20area%7D%7D%7B%5Cstackrel%7Bbase%7D%7B%2812%5Ccdot%2012%29%7D%2B%5Cstackrel%7B4~triangles%7D%7B4%5Cleft%5B%5Ccfrac%7B1%7D%7B2%7D%2812%29%286%5Csqrt%7B3%7D%29%20%5Cright%5D%7D%7D%5Cimplies%20144%20%2B%20144%5Csqrt%7B3%7D~~%5Capprox%20~~393.42)