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2 years ago

Does anyone know how to do this ? please help i don’t know how to . all three if you can :(

Mathematics

1 answer:

murzikaleks [220]2 years ago

7 0

Number 3 is 10 seconds.

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HELP!

maksim [4K]

Part A

$4x^2 -7x-15=0\\\\(4x+5)(x-3)=0\\\\x=-\frac{5}{4}, 3$

So, the x-intercepts are $\boxed{\left(-\frac{5}{4}, 0 \right), (3,0)}$

Part B

The vertex will be a minimum because the coefficient of $x^2$ is positive.

The x-coordinate of the vertex is $x=-\frac{-7}{2(4)}=\frac{7}{8}$

Substituting this back into the function, we get $f\left(\frac{7}{8} \right)=4\left(\frac{7}{8} \right)^2 -7\left(\frac{7}{8} \right)^2 -15=-\frac{289}{16}$

So, the coordinates of the vertex are $\boxed{\left(\frac{7}{8}, -\frac{289}{16} \right)}$

Part C

Plot the vertex and the x-intercepts and draw a parabola that passes through these three points.

The graph is shown in the attached image.

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1 year ago

Tyrone is converting 40/50 to a percent. Which method should he use to find the percent?

alex41 [277]

Answer: A

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

What is the factored form of x^3 -1

lianna [129]

Answer:

The factored form of x^3 -1 will be:

$x^3-1^3=\left(x-1\right)\left(x^2+x+1\right)$

Step-by-step explanation:

Given the expression

$x^3-1$

Rewrite 1 as 1³

$=x^3-1^3$

$\mathrm{Apply\:Difference\:of\:Cubes\:Formula:\:}x^3-y^3=\left(x-y\right)\left(x^2+xy+y^2\right)$

$x^3-1^3=\left(x-1\right)\left(x^2+x+1\right)$

$=\left(x-1\right)\left(x^2+x+1\right)$

Thus, the factored form of x^3 -1 will be:

$x^3-1^3=\left(x-1\right)\left(x^2+x+1\right)$

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2 years ago

Common difference between 3,8,13,18,23,28....

Natasha2012 [34]

Just keep adding 5 to the number

6 0

2 years ago

Read 2 more answers

Square EFGH underwent several transformations.

MariettaO [177]

Answer:

d=0.25

Step-by-step explanation:

4 + 4*d = 5

4d = 1

d =0.25

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2 years ago