The distance between Car A and car B,When Car A crosses the start line is:
distance =speed car B* time
distance=(15 m/s)(3 s)=45 m
Distance traveled by car A =x, (when the car B is at the same distance from the start line)
time of car A=t
x=10 m/st ⇒ x=10t (1)
Distance traveled by car B=x
time of car B=t-3
x=15(t-3) (2)
With the equations (1) and (2) we make a system of equations:
x=10t
x=15(t-3)
We solve this system of equations:
10t=15(t-3)
10t=15t-45
-5t=-45
t=-45 / -5
t=9
t-3=9-3=6
x=10 t=10 (9)=90
Answer: The time would be 9 seconds for Car A and 6 seconds for car B and the distance would be 90 meters.
Answer:
4/9
Step-by-step explanation:
The slope of these points would be: (5-1)/(3+6) = 4/9
Answer:37 and half hrs
Step-by-step explanation:
This is what I get
Myra: 50/2= 25 bulbs/hr.
Francis: 45/3= 15 bulbs/ hr
25+15= 40/hr. Together per hr
Need to find 150 bulbs how many hrs
40/1=150/t
40t=150
T= 150/4
T= 37.5
37hrs and 1/2
Answer:
Step-by-step explanation:
its wierd but 2.22
Answer:
(x+7)^2+4
Step-by-step explanation:
(x+7)^2 + 4
x^2+14x+49+4
x^2+24x+53
