Answer:
a.
capacity of car = 14 gallons
consumption of fuel in one day = 0.6 gallons
consumption of fuel in 14 days = 14 x 0.6 = 8.4 gallons
fuel remaining in car = 14 - 8.4 = 5.6 gallons
so they can drive the car without warning.
b.
consumption of fuel in one day = 0.6 gallons
consumption of fuel in 25 days = 25 x 0.6 = 15 gallons
fuel remaining in car = 14 - 15 = -1 gallons
so they can't drive the car without warning.
c.
the expression 14 - 0.6t represents remaining fuel in the vehicle, where t represents number of days.
d.
14 - 0.6t = 1.5
or - 0.6t = 1.5 - 14 = - 12.5
or t = -12.5 / - 0.6
or t = 20.8333 days
so he can drive 20 days without warning. E.
14 - 0.6t < 1.5
or t < 20.8333
here t represents number of days car can drive without warning light.
Step-by-step explanation:
The inequality is
The maximum number of days that Diego's father can drive the car without the warning light coming on is 20 days
14 gallons-1.5 gallons=12.5 gallons
we know that
If the remaining fuel is greater than 1.5 gallons Diego's father can drive the car without the warning light coming on
so
Let
x ----> the number of days
----> inequality that represent the situation
Solve for x
The maximum number of days that Diego's father can drive the car without the warning light coming on is 20 days
