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alex41 [277]
3 years ago
14

The value of a boat is $23,400. It loses 8% of its value every year. Find the approximate monthly percent decrease in value. Rou

nd your answer to the nearest hundredth of a percent.
NOT 67% OR 8.4!!!!
Mathematics
2 answers:
Zanzabum3 years ago
7 0

Answer:

23400 x 8/100 = 1872 = the loss  

1872 : 12 = 156= the loss each month  

156/1872*100% = 8.33 % then round it

DaniilM [7]3 years ago
4 0

23400 x 8/100 = 1872 = the loss  

1872 : 12 = 156= the loss each month  

156/1872*100% = 8.33 % then round it

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The area of a circle is equal to 1 dm2. Find the radius of the circle.
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Answer:

2000

Step-by-step explanation:

1 dm =1000

2dm =?

2dm x 1000

1dm

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What is the quotient (3x4 + 4x – 15) + (x + 3)?
Hoochie [10]

Answer:

3x-5 and r=0

Step-by-step explanation:

We can do it by long division method  the required quotient is 3x-5 and r=0

not 3x-1 , r=1

multiply the divisor with 3x  we will get to cancel out the first term of dividend

Now after solving we will get  

Now, multiply the divisor by -5 we will get -5x-15 which will cancel the entire dividend.

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3 years ago
EXTRA POINTS! volume of spheres.
BartSMP [9]

Answer:

V≈33.51

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3 years ago
Need an answer as soon as possible.
Elza [17]
Part A

Answer: The common ratio is -2

-----------------------------------

Explanation: 

To get the common ratio r, we divide any term by the previous one

One example:
r = common ratio
r = (second term)/(first term)
r = (-2)/(1)
r = -2

Another example:
r = common ratio
r = (third term)/(second term)
r = (4)/(-2)
r = -2
and we get the same common ratio every time

Side Note: each term is multiplied by -2 to get the next term

============================================================
Part B

Answer:
The rule for the sequence is 
a(n) = (-2)^(n-1)
where n starts at n = 1

-----------------------------------

Explanation:

Recall that any geometric sequence has the nth term
a(n) = a*(r)^(n-1)
where the 'a' on the right side is the first term and r is the common ratio

The first term given to use is a = 1 and the common ratio found in part A above was r = -2
So,
a(n) = a*(r)^(n-1)
a(n) = 1*(-2)^(n-1)
a(n) = (-2)^(n-1)

============================================================
Part C

Answer: The next three terms are 16, -32, 64

-----------------------------------

Explanation:

We can simply multiply each previous term by -2 to get the next term. Do this three times to generate the next three terms

-8*(-2) = 16
16*(-2) = -32
-32*(-2) = 64

showing that the next three terms are 16, -32, and 64

An alternative is to use the formula found in part B

Plug in n = 5 to find the fifth term
a(n) = (-2)^(n-1)
a(5) = (-2)^(5-1)
a(5) = (-2)^(4)
a(5) = 16 .... which matches with what we got earlier

Then plug in n = 6
a(n) = (-2)^(n-1)
a(6) = (-2)^(6-1)
a(6) = (-2)^(5)
a(6) = -32 .... which matches with what we got earlier

Then plug in n = 7
a(n) = (-2)^(n-1)
a(7) = (-2)^(7-1)
a(7) = (-2)^(6)
a(7) = 64 .... which matches with what we got earlier

while the second method takes a bit more work, its handy for when you want to find terms beyond the given sequence (eg: the 28th term)
6 0
3 years ago
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