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Tomtit [17]
3 years ago
9

The energy required to overcome the attraction between two bonded nuclei and their shared electrons is called _____ energy. This

quantity is a measure of bond strength since the stronger the bond, the _____ the amount of energy required to break it.
Chemistry
2 answers:
omeli [17]3 years ago
7 0

Answer:

<em>Nuclear Binding Energy (Bond Energy), Higher (Greater)</em>

Explanation:

<em>The energy required to overcome the attraction between two bonded nuclei and their shared electrons is called </em><em>Nuclear Binding</em><em> </em><em>Energy (Bond Energy)</em><em>. This quantity is a measure of bond strength since the stronger the bond, the </em><em>Higher (Greater) </em><em>the amount of energy required to break it.</em>

Levart [38]3 years ago
6 0

The energy required to overcome the attraction between two bonded nuclei and their shared electrons is called bond energy. This quantity is a measure of bond strength since the stronger the bond, the greater amount of energy required to break it.

I hope this helps!

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1. The atomic number of an element is 23 and its mass number is 56. a. How many protons and electrons does an atom of this eleme
Arte-miy333 [17]

Answer:

There are 23 protons and 23 electrons. We know this because atomic number denotes the number of protons and also electrons. There are 56 - 23 = 33 neutrons because atomic mass denotes the total number of protons and neutrons.

7 0
4 years ago
1. 7.85 g of sodium metal is added to 200 mL of 0.0450 M HNO3
kumpel [21]

Answer:

a)0.765 g

b)7.613 g

c)0.20 L

Explanation:

Consider the reaction involved;

Na(s) + HNO3(aq) ----> NaNO3(s) + H2(g)

Note that, if a hot, saturated aqueous solution of sodium nitrate was allowed to cool, solid sodium nitrate would crystallise out of the solution and this would also be classed as a precipitate. This is the case here.

Number of moles of sodium reacted= mass of sodium reacted/ molar mass of sodium

Number of moles of sodium= 7.85g/23gmol-1

Number of moles of sodium= 0.34 moles of sodium

Number of moles of acid reacted= concentration of acid × volume of acid

Number of moles of acid= 0.0450 × 200/1000

Number of moles of acid= 9×10^-3 moles

Therefore, HNO3 is the limiting reactant.

1 mole of HNO3 yield 1 mole of NaNO3

9×10^-3 moles of HNO3 yield 9×10^-3 moles of NaNO3

Hence mass of NaNO3= number of moles × molar mass

Mass of NaNO3= 9.0×10^-3 moles × 84.9947 g/mol

Mass of NaNO3= 0.765 g of NaNO3

b)

Since

1 mole of sodium metal reacts with 1 mole of HNO3

9×10^-3 moles of sodium reacts with 9×10^-3 moles of HNO3

Therefore amount of unreacted sodium metal = 0.34 moles - 9×10^-3 moles = 0.331 moles

Mass of unreacted sodium metal = 0.331 moles × 23 gmol-1= 7.613 g

c)

If 1 mole of HNO3 yields 1 mole of hydrogen gas

9×10^-3 moles of HNO3 yields 9×10^-3 moles of hydrogen gas.

1 mole of hydrogen gas occupies 22.4 L

9×10^-3 moles of hydrogen gas will occupy 9×10^-3 moles × 22.4/1 = 0.20 L

3 0
3 years ago
For each reaction, find the value of ΔSo. Report the value with the appropriate sign. (a) 3 NO2(g) + H2O(l) → 2 HNO3(l) + NO(g)
aev [14]

Answer:

ΔS° = -268.13 J/K

Explanation:

Let's consider the following balanced equation.

3 NO₂(g) + H₂O(l) → 2 HNO₃(l) + NO(g)

We can calculate the standard entropy change of a reaction (ΔS°) using the following expression:

ΔS° = ∑np.Sp° - ∑nr.Sr°

where,

ni are the moles of reactants and products

Si are the standard molar entropies of reactants and products

ΔS° = [2 mol × S°(HNO₃(l)) + 1 mol × S°(NO(g))] - [3 mol × S°(NO₂(g)) + 1 mol × S°(H₂O(l))]

ΔS° = [2 mol × 155.6 J/K.mol + 1 mol × 210.76 J/K.mol] - [3 mol × 240.06 J/K.mol + 1 mol × 69.91 J/k.mol]

ΔS° = -268.13 J/K

7 0
3 years ago
Which of the following molecules would be the best hydrogen bond donor?
leva [86]

Answer: Option (d) is the correct answer.

Explanation:

When a hydrogen atom comes in contact with an electronegative atom then it results in the formation of a chemical bond.

More is the electronegativity of combining atom, more stronger will be the bond with hydrogen atom. As a result, the compound formed will not easily give up hydrogen atom upon dissociation.

Whereas less is the electronegativity of atom combining with hydrogen atom, easily it will donate the hydrogen atom upon dissociation.

Since, out of the given option sulfur (S) atom has low electronegativity as compared to oxygen and nitrogen atom.

Hence, CH_{3}SH will easily donate hydrogen atom.

Thus, we can conclude that CH_{3}SH molecule would be the best hydrogen bond donor.

4 0
3 years ago
Who was Lucy, the Australopithecus afarensis?
Nostrana [21]

Answer:

c i believe

Explanation:

Good luck and sorry if im wrong

7 0
3 years ago
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