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UNO [17]
3 years ago
6

Substance A is added to water. After it is added, hydrogen ions are produced and accumulate in the

Chemistry
1 answer:
Katena32 [7]3 years ago
4 0

Substance A is an acid.

Substance B is a group of hydronium ions.

Explanation:

From the description above, we can deduce that substance A is an acid whereas substance B is a group of hydroxonium ions.

An acid can be defined as a substance that produces hydrogen ions in solution.

Acids interacts with water to produce excess hydroxonium ions, H₃O⁺ in an aqueous solution.

The hydroxonium ions results from the chemical bonding between oxygen of water molecules and protons released by the ionization of the acid:  

                    HCl + H₂O → H₃O⁺  +  Cl⁻

Learn more:

Acid brainly.com/question/5121777

#learnwithBrainly

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What is the composition, in atom percent, of an alloy that contains a) 45.5 lbm of silver, b) 83.7 lbm of gold, and c) 6.3 lbm o
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Answer:

\% atAg=44.6\%\\\% atAu=44.9\%\\\% atCu=10.5\%

Explanation:

Hello,

In this case, for computing the atom percent, one must obtain the number of atoms of silver, gold and copper as shown below:

atomsAg=45.5lbm*\frac{453.59g}{1lbm}*\frac{1molAg}{107.87gAg}*\frac{6.022x10^{23}atomsAg}{1molAg}=1.15x10^{26}atomsAg\\atomsAu=83.7lbm*\frac{453.59g}{1lbm}*\frac{1molAu}{196.97gAu}*\frac{6.022x10^{23}atomsAu}{1molAu}=1.16x10^{26}atomsAu\\atomsCu=6.3lbm*\frac{453.59g}{1lbm}*\frac{1molAg}{63.55gCu}*\frac{6.022x10^{23}atomsCu}{1molCu}=2.71x10^{25}atomsCu

Thus, the atom percent turns out:

\% atAg=\frac{1.15x10^{26}}{1.15x10^{26}+1.16x10^{26}+2.71x10^{25}}*100\% =44.6\%\\\% atAu=\frac{1.16x10^{26}}{1.15x10^{26}+1.16x10^{26}+2.71x10^{25}}*100\% =44.9\%\\\% atCu=\frac{2.71x10^{25}}{1.15x10^{26}+1.16x10^{26}+2.71x10^{25}}*100\% =10.5\%

Best regards.

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