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3 years ago

For each reaction, find the value of ΔSo. Report the value with the appropriate sign. (a) 3 NO2(g) + H2O(l) → 2 HNO3(l) + NO(g)

Chemistry

1 answer:

aev [14]3 years ago

7 0

Answer:

ΔS° = -268.13 J/K

Explanation:

Let's consider the following balanced equation.

3 NO₂(g) + H₂O(l) → 2 HNO₃(l) + NO(g)

We can calculate the standard entropy change of a reaction (ΔS°) using the following expression:

ΔS° = ∑np.Sp° - ∑nr.Sr°

where,

ni are the moles of reactants and products

Si are the standard molar entropies of reactants and products

ΔS° = [2 mol × S°(HNO₃(l)) + 1 mol × S°(NO(g))] - [3 mol × S°(NO₂(g)) + 1 mol × S°(H₂O(l))]

ΔS° = [2 mol × 155.6 J/K.mol + 1 mol × 210.76 J/K.mol] - [3 mol × 240.06 J/K.mol + 1 mol × 69.91 J/k.mol]

ΔS° = -268.13 J/K

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Propenoic acid, C3H4O2, is a reactive organic liquid that is used in the manufacturing of plastics, coatings, and adhesives. An

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Answer:

C = 39%

H = 5.43%

Explanation:

Firstly, we calculate the number of moles of each.

For carbon, we use carbon iv oxide

Mass here = 0.636g

Number of moles of carbon iv oxide = mass of carbon iv oxide ÷ molar mass of carbon iv oxide. Molar mass = 44g/mol

Number of moles = 0.636 ÷ 44 = 0.014mole

Since 1 mole of carbon iv oxide contains 1 mole carbon, 0.014 mole of carbon iv oxide is also produced.

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For hydrogen, we use water .

Mass of water = 0.220g

No of moles of water = 0.22 ÷ 18 = 0.012 mole

1 mole of water has two moles of hydrogen, thus the amount of hydrogen produced = 0.012 × 2 = 0.024mole

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3 years ago