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Elina [12.6K]
3 years ago
10

Is 10 the solution of the equation 4x - 8 = 31?

Mathematics
2 answers:
Tom [10]3 years ago
6 0
4x-8 = 31

4x = 31 + 8

4x = 39

x = 9.75
Vitek1552 [10]3 years ago
3 0
4x - 8 = 31
4x = 39
x = 9.75
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Answer:

D) college students

The college students are best describes the population

Step-by-step explanation:

<u>Explanation</u>:-

<u>Introduction</u>:-

The outcome of a statistical experiment may be recorded either as a numerical value or as a descriptive representation.

<u>Example</u>:-

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In particular study, the number of possible observations may be <u>small, large but finite or infinite.</u>

<u> Example :- 1</u>

In the classification of blood types we can only have as many observations as there are students in the school.

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<u>Example :- 2</u>

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<u>Population</u>:-

The total of observations which we are concerned , whether this number is finite or infinite , this is called the<u> population</u>

The number of observations in the population is defined to be the size of the population.

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<u>Sample</u>:- A sample is subset of a population

Therefore in given data

The college students are best describes the population

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7 0
3 years ago
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jenyasd209 [6]

Code:!#@$% Means there is a "Cuss word for adults to say"

7 0
3 years ago
Bonjour
solmaris [256]
<span>3 + t = 2 x t + 7    t =4 et x=0   vraie
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No, 25 cm c'est un 40 ou 41
No 23 cm c'est un 37



</span>
6 0
4 years ago
Twice as many students are in the chess club as in the fencing club.The number of students in the fencing club is one fifth the
jekas [21]

Answer:

28 students

Step-by-step explanation:

Let number of students in cooking club = x

Number of students in fencing club = 1/5 x

Number of students in chess club = 2(1/5)x

Since, There are 42 more students in the cooking club than in the chess club

Then ;

Number of students in chess club = Number of students in cooking club - 42

2(1/5)x = x - 42

(2/5)x - x = - 42

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-0.6x = - 42

x = 42 / 0.6

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Hence, number of students in chess club :

(2/5) * 70 = 28

4 0
3 years ago
Which relation defined by a mapping diagram is not a function?
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