Answer:
if sin (x-3) degrees = cos (2x+6) degrees, find the value of x.
----------
Note: sin and cos are complementary functions....
sin(x) = cos (90-x)
-------------------
Your Problem:
sin(x-3) = cos(90-(x-3))
Equation:
90-[x-3] = 2x+6
90-x+3 = 2x+6
3x = 93-6
x = 31-2
x = 29
Step-by-step explanation:
The standard form of a line is in the form

A, B and C are integers, and A is positive. Let's start with multiplying the whole equation by 3 to get rid of denominators:

Subtract 3y from both sides:

Which of course is equivalent to

Which is the standard form, given the coefficients A=1, B=-3, C=6.
Circumference of circle = π × Diameter
= π × 18 cm
= 56.54867 or 56.54 to 1 dp