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3 years ago

Pls help me 10 points

Mathematics

1 answer:

Bas_tet [7]3 years ago

6 0

Answer:

Yes

Step-by-step explanation:

A proportional relationships occurs when the line of a graph passes or starts at the origin and in this case, it does.

Best of Luck!

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Find the value of x.

Genrish500 [490]

Answer:

Step-by-step explanation:

All angles on a triangle equal 180. 80+60=140.

Now to solve for x, we set it to equal 40 for 180-140.

40=3x+7. 40-7=33

33=3x 33/3=11

x=11

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Determine the measure of EBD

Soloha48 [4]

Answer:

Answer:

EBD= 156

Step-by-step explanation:

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Mark as Brainlist

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The x - intercept of the function f(x) = x2 + 4x - 12 is:

Assoli18 [71]

Answer:

C) (-6,0)(2,0)

For x-intercept, f(x) = 0:

${ \tt{ {x}^{2} + 4x - 12 = 0 }} \\ { \tt{(x - 2)(x + 6) = 0}}$

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2 years ago

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The managers of 21 supermarkets counted the number of cars in their parking lots on the same day. The results are shown in the l

mixer [17]

The IQR is 42.5

Step-by-step explanation:

Interquartile range is the difference of third and first quartile.

First of all we have to find the median for that purpose the data has to be arranged in ascending order. The data is already in ascending order.

As the number of values are odd

n=21

The median will be: $(\frac{n+1}{2}) th\ term$

Putting n=21

$(\frac{21+1}{2})th\ term\\=(\frac{22}{2})th\ term\\= 11th\ term$

The 11th term is 133

So median = 133

Now the data is divided into two halves

One is: 98, 100, 101, 102, 108, 109, 111,118, 129, 132

2nd is: 135, 135, 145, 146, 146, 156, 170 176, 180, 180

Q1 will be the median of first half and Q3 will be the median of 2nd half.

As now the halves contain even number of values, the medians will be the average of middle two values

For First Half:

98, 100, 101, 102, 108, 109, 111,118, 129, 132

$Q_1 = \frac{108+109}{2}\\Q_1 = \frac{217}{2}\\Q_1 = 108.5$

For Second Half:

135, 135, 145, 146, 146, 156, 170 176, 180, 180

$Q_2 = \frac{146+156}{2}\\Q_2 = \frac{302}{2}\\Q_2 = 151$

Now

Interquartile Range:

$IQR = Q_3-Q_1\\= 151-108.5\\=42.5$

Hence,

The IQR is 42.5

Keywords: Median, IQR

Learn more about median at:

#LearnwithBrianly

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2 years ago