<h3>
Answer:</h3>
A. 28
<h3>
Step-by-step explanation:</h3>
We assume m is the measure of the marked unknown angles: ∠BZY ≅ ∠BZA
(5x +3)° = (2x +18)°
Divide by ° and subtract 2x+3:
... 3x = 15
... x = 5
Then ∠BZA = (2·5 +18)° = m = 28°
0.08*x+0.03*(29000-x)<span> </span>
Complete question :
Birth Month Frequency
January-March 67
April-June 56
July-September 30
October-December 37
Answer:
Yes, There is significant evidence to conclude that hockey players' birthdates are not uniformly distributed throughout the year.
Step-by-step explanation:
Observed value, O
Mean value, E
The test statistic :
χ² = (O - E)² / E
E = Σx / n = (67+56+30+37)/4 = 47.5
χ² = ((67-47.5)^2 /47.5) + ((56-47.5)^2 /47.5) + ((30-47.5)^2/47.5) + ((37-47.5)^2/47.5) = 18.295
Degree of freedom = (Number of categories - 1) = 4 - 1 = 3
Using the Pvalue from Chisquare calculator :
χ² (18.295 ; df = 3) = 0.00038
Since the obtained Pvalue is so small ;
P < α ; We reject H0 and conclude that there is significant evidence to suggest that hockey players' birthdates are not uniformly distributed throughout the year.
Answer:
0.16
Step-by-step explanation: