Step-by-step explanation:
Let the height above which the ball is released be H
This problem can be tackled using geometric progression.
The nth term of a Geometric progression is given by the above, where n is the term index, a is the first term and the sum for such a progression up to the Nth term is
To find the total distance travel one has to sum over up to n=3. But there is little subtle point here. For the first bounce ( n=1 ), the ball has only travel H and not 2H. For subsequent bounces ( n=2,3,4,5...... ), the distance travel is 2×(3/4)n×H
a=2H..........r=3/4
However we have to subtract H because up to the first bounce, the ball only travel H instead of 2H
Therefore the total distance travel up to the Nth bounce is
For N=3 one obtains
D=3.625H
Answer:
47/30
Step-by-step explanation:
2.35 * 2/3 =
= 2 35/100 * 2/3
= 2 7/20 * 2/3
= 47/20 * 2/3
= 94/60
= 47/30
Answer:
12.247 Hope I helped
Step-by-step explanation:
Finished:Left
8:1
8/1 = 72/x
Cross Multiply
8x=72
divide each side by 8
x=9
She already finished 72 and has 9 remaining
Total = Finished + Remaining = 72 + 9 = 81
A.
because the total distance of every triangle 180. Add the two other angles so 42+ 57 =99. Then you have to subtract those two combined angles to find the missing one from the total distance, which is 180. 180-99=81. the answer is A. 81
