Please help me this is impossible

Mathematics

2 answers:

ratelena [41]4 years ago

7 0

1. Combine like terms, so add 2.4 to -4.8 to get -2.4
So now you should be left with .02(x+20)-2.4=-9
2. Now eliminate the -2.4 by adding 2.4 to both sides, getting .02(x+20)=-6.6
3. Multiply everything by 50 to make x+20=-333, since 50×.02=1
4. subtract 20 from both sides to get x=-353

Alex Ar [27]4 years ago

3 0

We need to distribute the parenthesis before we do anything. 0.02(x+20)=0.02x+0.4; now let's put this into the equation.

2.4+0.02x+0.4-4.8=-9; this is all about making sure we get x on one side, isolated. We need to add all the like terms.

0.02x-2=-9; let's add 2 to both sides. 0.02x=-7; let's divide each side by 0.02 so that we can have x by itself. x=-350; let's plug -350 in as in the original equation to make sure that is our answer.

2.4+0.02(-350+20)-4.8=-9; let's add the parenthesis. 2.4+0.02(-330)-4.8=-9; let's multiply. 2.4-6.6-4.8=-9; let's subtract. 2.4-6.6=-4.2-4.8=-9

So, x=-350.

You might be interested in

Determine whether each function is an example of exponential growth or decay. Then, find the y -intercept. y=25/7(7/5) x

Olenka [21]

y = 25x / 5 is each function is an example of exponential growth or decay.

What does exponential growth look like in math?

A typical illustration of exponential expansion is population increase. Take a population of bacteria as an example. It seems sense that the rate of population increase would be inversely correlated with the population's size.
After all, the number of bacteria grows more quickly the more there are for them to reproduce.

y= 25/7(7/5) x

y = 25/5 x

y = 25x / 5

Learn more about exponential growth

brainly.com/question/11487261

#SPJ4

7 0

2 years ago

The y coordinate of the vertex of f (x)=-x^2+8x+7 is f(4)

azamat

Hello there.

To answer this question, we need to remember some properties about the vertex of quadratic functions.

Let $f(x)=ax^2+bx+c,~a\neq0$ . Its vertex can be found on the coordinates $(x_v,~y_v)$ such that $x_v=-\dfrac{b}{2a}$ and $y_v=-\dfrac{b^2}{4a}+c$ , in which $y_v=f(x_v)$ .