Answer:A, you would weigh the same on both planets because their masses and the distance to their centers of gravity are the same
Explanation:
Answer:
A=1.0.34 m
Explanation:
Given that
f= 1 s
x= 1 m
v = 1.72 m/s
We know that angular frequency ω is given as
ω = 2 π f
Now by putting the values in the above equation
ω = 2 π x 1
ω= 2 π rad/s
The velocity v is given as
A=Amplitude
A=1.0.34 m
KE = 1/2mv^2
m=10 v=3
KE=1/2*10*3^2
KE= 45 Joules
1.47x10^5 Joules
The gravitational potential energy will be the mass of the object, multiplied by the height upon which it can drop, multiplied by the local gravitational acceleration. And since it started at the top of a 60.0 meter hill, halfway will be at 30.0 meters. So
500 kg * 30.0 m * 9.8 m/s^2 = 147000 kg*m^2/s^ = 147000 Joules.
Using scientific notation and 3 significant figures gives 1.47x10^5 Joules.
Answer:
The sound intensity of source #2 is 38.3 W/m²
Explanation:
Given;
sound intensity of source #1, I₁ = 38.3 W/m²
sound intensity of source #2, I₂ = 2.6 dB greater than 38.3 W/m²
To determine he sound intensity of source #2 in W/m², we must convert 2.6 dB to sound intensity in W/m².
Thus, sound intensity of source #2 = 38.3 W/m² + 1.8197 x 10⁻¹² W/m² = 38.3 W/m²
Therefore, the sound intensity of source #2 is 38.3 W/m²