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ss7ja [257]
3 years ago
15

The moment of inertia of a uniform equilateral triangle with mass m and side length a about an axis through one of its sides and

parallel to that side is (1/8) ma^2. What is the moment of inertia of a uniform regular hexagon of mass m and side length a about an axis through two opposite vertices?
Physics
1 answer:
Bond [772]3 years ago
8 0
No Idea sir skskskhhhhfffvftujbvf
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(a) The free body of all the forces include, frictional force, weight of the box acting perpendicular and another acting parallel to the plane.

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(c) When the box slides up, the direction of the frictional force changes, it acts towards the left.

<h3>Free body diagram</h3>

The free body diagram of all the forces on the box is obtained by noting the upward force and downward forces on the box as shown below;

                      /  W2

                    Ф → Ff

                    ↓W1

where;

  • Ff is the frictional force resisting the down motion of the box
  • W1 is the perpendicular component of the box weight = Wcos(33)
  • W2 is the parallel component of the box weight = Wsin(33)

(b) When the box is sliding down, the frictional force acts towards the right.

(c) When the box slides up, the direction of the frictional force changes, it acts towards the left.

Learn more about free body diagram of inclined objects here: brainly.com/question/4176810

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The given statement is false.

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So, the given statement is false as a concave mirror always forms a real and inverted image. Hence, this is the required solution.

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3 years ago
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