3 years ago

What is the value of the expression 9 − ( fraction 1 over 2 )4 ⋅ 48?

Mathematics

2 answers:

vovikov84 [41]3 years ago

8 0

The value of the given expression is 6.

Sergeu [11.5K]3 years ago

4 0

Answer:

9 - (1/2)^4 x48

9 - 1/16 x 48

9 - 3 = 6

Step-by-step explanation:

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I need help :( this problem is very confusing

Sladkaya [172]

Answer:

Emily , don't put your whole name in the questions :DDDD, it's at the top of the page, anyway, Eloper .. :DDD

Step-by-step explanation:

It's arithmetic b/c you're just adding 1

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6 0

3 years ago

Read 2 more answers

19. 4x-y+2z =<br> 8x+y-4<br> Find x

Varvara68 [4.7K]

Answer:

x = $\frac{4-2y+2z}{4}$

Step-by-step explanation:

4x-y+2z = 8x+y-4

4x-8x-y+2z = 8x - 8x +y-4

-4x -y +2z= y-4

-4x -y+y +2z = y+y-4

-4x +2z = 2y-4

-4x+2z-2z = 2y-2z-4

-4x = 2y-2z-4

$x= \frac{2y-2z-4}{-4}$ = $\frac{4-2y+2z}{4}$

4 0

3 years ago

What is -0.009 to the second power

kondaur [170]

I believe it's -0.000081

5 0

3 years ago

Imagine that you need to compute e^0.4 but you have no calculator or other aid to enable you to compute it exactly, only paper a

labwork [276]

Answer:

0.0032

Step-by-step explanation:

We need to compute $e^{0.4}$ by the help of third-degree Taylor polynomial that is expanded around at x = 0.

Given :

$e^{0.4}$ < e < 3

Therefore, the Taylor's Error Bound formula is given by :

$|\text{Error}| \leq \frac{M}{(N+1)!} |x-a|^{N+1}$ , where $M=|F^{N+1}(x)|$

$\leq \frac{3}{(3+1)!} |-0.4|^4$

$\leq \frac{3}{24} \times (0.4)^4$

$\leq 0.0032$

Therefore, |Error| ≤ 0.0032

4 0

3 years ago

Six subtracted from a number

Klio2033 [76]

Answer:

X-6

Step-by-step explanation:

Represent the unknown number with a variable then introduce the minus sign

8 0

3 years ago