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Gennadij [26K]
3 years ago
12

Cuánto costará cercar una finca cuadrada de 14 metros de lado a razón de $150 el metro lineal de alambrada

Mathematics
1 answer:
disa [49]3 years ago
6 0

Answer:

$ 2100

Step-by-step explanation:

De la pregunta anterior:

1 metro de cerca de alambre = $ 150

14 metros = x

Cruz multiplicar

x = 14 × $ 150

x = $ 2100

Por lo tanto, costaría $ 2100 por una cerca de 14 metros

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2 years ago
Y''+y'+y=0, y(0)=1, y'(0)=0
mars1129 [50]

Answer:

y=e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+\frac{1}{\sqrt{3}}\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )

Step-by-step explanation:

A second order linear , homogeneous ordinary differential equation has form ay''+by'+cy=0.

Given: y''+y'+y=0

Let y=e^{rt} be it's solution.

We get,

\left ( r^2+r+1 \right )e^{rt}=0

Since e^{rt}\neq 0, r^2+r+1=0

{ we know that for equation ax^2+bx+c=0, roots are of form x=\frac{-b\pm \sqrt{b^2-4ac}}{2a} }

We get,

y=\frac{-1\pm \sqrt{1^2-4}}{2}=\frac{-1\pm \sqrt{3}i}{2}

For two complex roots r_1=\alpha +i\beta \,,\,r_2=\alpha -i\beta, the general solution is of form y=e^{\alpha t}\left ( c_1\cos \beta t+c_2\sin \beta t \right )

i.e y=e^{\frac{-t}{2}}\left ( c_1\cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )

Applying conditions y(0)=1 on e^{\frac{-t}{2}}\left ( c_1\cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right ), c_1=1

So, equation becomes y=e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )

On differentiating with respect to t, we get

y'=\frac{-1}{2}e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )+e^{\frac{-t}{2}}\left ( \frac{-\sqrt{3}}{2} \sin \left ( \frac{\sqrt{3}t}{2} \right )+c_2\frac{\sqrt{3}}{2}\cos\left ( \frac{\sqrt{3}t}{2} \right )\right )

Applying condition: y'(0)=0, we get 0=\frac{-1}{2}+\frac{\sqrt{3}}{2}c_2\Rightarrow c_2=\frac{1}{\sqrt{3}}

Therefore,

y=e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+\frac{1}{\sqrt{3}}\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )

3 0
3 years ago
Giving brainlyest if your answer is right
sineoko [7]

Answer:

-77

Step-by-step explanation:

give brainliest

6 0
3 years ago
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Write x^5 • x^7 as a single exponential expression
Aleks [24]
Answer: x^12
Explanation: When the base (x) is the same and they are being multiplied the exponents are added. This is called/because of “The Product Rule for Exponents”.
4 0
2 years ago
Which pair shows equivalent expressions?2(3x+ 2) = 23 x+1<br> 21ę x+ 2) = x+4<br> 2c 21= x+4)= 2
Ket [755]

Answer:

Option (2)

Step-by-step explanation:

Option (1).

2(\frac{2}{5}x+2)=2\frac{2}{5}x+1

\frac{4x}{5}+4=\frac{12}{5}x+1

Therefore, both the sides of the expression are not equal.

False.

Option (2).

2(\frac{2}{5}x+2)=\frac{4}{5}x+4

\frac{4x}{5}+4=\frac{4}{5}x+4

True.

Option (3).

2(\frac{2}{5}x+4)=\frac{4}{5}x+2

\frac{4}{5}x+8=\frac{4}{5}x+2

False.

Option (4).

2(\frac{2}{5}x+4)=2\frac{2}{5}x+8

\frac{4x}{5}+8=\frac{12}{5}x+8

Both the sides are not equal.

False.

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3 years ago
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